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Perl (preg) Regular Expression

Posted on 2004-10-11
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Last Modified: 2013-12-12
                       Need to match anythign like the following:
                        Firstname Lastname [Y] (sdsdd 45)
                        Firstname Lastname (sdsdd 45)
                        Firstname Lastname [R] (sdsdd 45)
                        Firstname Lastname [Y][R] (sdsdd 45)

                        This is for my football site I am trying to develop were [Y] and [R] are yellow and
                        red cards respectively.  Anything brackets reprsents a substitution.
                        I have the following that only partially works:
                        
                        $pattern = '/'.$player.' \((.*?)\)/mis';
                        
                        This matches all players that have not been given a card but have been substituted.  This however won't work:
                        
                        $pattern = '/'.$player.' (\[Y|R\])* \((.*?)\)/mis';
                        
                        It is meant to detect players that may or may not have been given a card but have been substituted.  
                        
                        Any ideas gratefully recieved.
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Question by:Ape
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LVL 48

Expert Comment

by:hernst42
ID: 12275750
You ned to put a subpattern () arount the Y|R else this means for the regecx
[Y or R] but not [(Y or R)]
$pattern = '/'.$player.' (\[(Y|R)\])* \((.*?)\)/mis';
or write it as
$pattern = '/'.$player.' (\[[YR]\])* \((.*?)\)/mis';

if ue it for a preg_replace you will get the last macht (R) if both Y and R are present.
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Author Comment

by:Ape
ID: 12276461
Thanks.

 That still doesn't work.  For some reason using that it doesn't match on anything: Two examples.

firstname lastname (newplayer 33)
firstname lastname [Y] (newplayer 58)

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Accepted Solution

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hernst42 earned 1000 total points
ID: 12276766
Here is how I tested it:

$player = 'Firstname Lastname';
$str = 'Firstname Lastname [Y][R] (sdsdd 45)';
$pattern = '/'.$player.'\s*(\[(Y|R)\])* \((.*?)\)/mis';

preg_match($pattern, $str, $m);
var_dump($m);
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Author Comment

by:Ape
ID: 12277540
Sorry it was the matchign parameter in preg_match that I wasn't paying attention to.

Thanks for your help.
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