Still celebrating National IT Professionals Day with 3 months of free Premium Membership. Use Code ITDAY17

x
?
Solved

Run sqlldr in java

Posted on 2004-10-11
5
Medium Priority
?
1,932 Views
Last Modified: 2012-08-14
I want to run sqlldr on my machine. I use the code below:

public void doSqlLoader(){
       String s = null;            
       try {
      System.out.println("Starting SQLLOAD");
      String cmd = "sqlldr owner/owner@trdbd control=C:\\nd\\iaf.ctl  
                                 data=C:\\nd\\iaf_account_20040929.txt log=C:\\nd\\transfer.log errors=10000";
            
      Process p = Runtime.getRuntime().exec("cmd");
       p.waitFor();
       BufferedReader stdInput = new BufferedReader(new
       InputStreamReader(p.getInputStream()));
                  
       BufferedReader stdError = new BufferedReader(new
       InputStreamReader(p.getErrorStream()));

       // read the output from the command          
      
      while ((s = stdInput.readLine()) != null) {
               System.out.println(s);
       }
           
       // read any errors from the attempted command
       System.out.println("Here is the standard error of the command (if any):\n");
       while ((s = stdError.readLine()) != null) {
               System.out.println(s);
       }
         if ( p.exitValue() ==0)
         {
               System.out.println("\n\nSQLLOAD completed.");
          }
               } catch (IOException ioe){
                       System.out.println(ioe);
               }catch (InterruptedException ie){
         System.out.println(ie);
               }
}

It doesn't work and never generate a log file. Could you please help me for that?
Thanks.
                                        
0
Comment
Question by:jen2483
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 4
5 Comments
 
LVL 86

Expert Comment

by:CEHJ
ID: 12280303
>>It doesn't work

Meaning?
0
 
LVL 86

Expert Comment

by:CEHJ
ID: 12280409
Try

final String[] cmd = {
      "sqlldr",
      "owner/owner@trdbd",
      "control=C:\\nd\\iaf.ctl",
      "data=C:\\nd\\iaf_account_20040929.txt",
      "log=C:\\nd\\transfer.log errors=10000" };
RunAsync.main(cmd);      

with the following class:


//SNIP===============================================================

import java.io.*;

/**
 *  Description of the Class
 *
 * @author     Administrator
 * @created    23 February 2004
 */
public class RunAsync {

  /**
   *  Description of the Method
   *
   * @param  args  Description of the Parameter
   */
  public static void main(String args[]) {

    try {

      if (args.length < 1) {
        System.out.println("Usage: java RunAsync <command string>");
        System.exit(-1);
      }
      Process pro = null;
      if (args.length > 1) {
        pro = Runtime.getRuntime().exec(args);
      }
      else {
        pro = Runtime.getRuntime().exec(args[0]);
      }
      InputStream error = pro.getErrorStream();
      InputStream output = pro.getInputStream();
      Thread err = new Thread(new OutErrReader(error));
      Thread out = new Thread(new OutErrReader(output));
      out.start();
      err.start();
      pro.waitFor();
    }
    catch (java.io.IOException e) {
      e.printStackTrace();
    }
    catch (java.lang.InterruptedException e) {
      e.printStackTrace();
    }

  }


  /**
   *  Description of the Class
   *
   * @author     Administrator
   * @created    23 February 2004
   */
  static class OutErrReader implements Runnable {
    InputStream is;


    /**
     *Constructor for the OutErrReader object
     *
     * @param  is  Description of the Parameter
     */
    public OutErrReader(InputStream is) {
      this.is = is;
    }


    /**
     *  Main processing method for the OutErrReader object
     */
    public void run() {
      try {
        BufferedReader in = new BufferedReader(new InputStreamReader(is));
        String temp = null;
        while ((temp = in.readLine()) != null) {
          System.out.println(temp);
        }
        is.close();
      }
      catch (Exception e) {
        e.printStackTrace();
      }
    }
  }
}

0
 

Author Comment

by:jen2483
ID: 12280441
If it works, it should generate a log file under the directory I defined as C:\nd\transfer.log and the data should be insert into the table of the database. Now the code doesn't accomplish these purposes.
0
 
LVL 86

Accepted Solution

by:
CEHJ earned 2000 total points
ID: 12280475
Try with the code i posted
0
 
LVL 86

Expert Comment

by:CEHJ
ID: 12280861
8-)
0

Featured Post

Build and deliver software with DevOps

A digital transformation requires faster time to market, shorter software development lifecycles, and the ability to adapt rapidly to changing customer demands. DevOps provides the solution.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

This was posted to the Netbeans forum a Feb, 2010 and I also sent it to Verisign. Who didn't help much in my struggles to get my application signed. ------------------------- Start The idea here is to target your cell phones with the correct…
Introduction This article is the last of three articles that explain why and how the Experts Exchange QA Team does test automation for our web site. This article covers our test design approach and then goes through a simple test case example, how …
Viewers learn how to read error messages and identify possible mistakes that could cause hours of frustration. Coding is as much about debugging your code as it is about writing it. Define Error Message: Line Numbers: Type of Error: Break Down…
This tutorial covers a practical example of lazy loading technique and early loading technique in a Singleton Design Pattern.
Suggested Courses

688 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question