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How to create a java program that generates and prints a random phone number in the form xxx-xxx-xxxx

Posted on 2004-10-12
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Last Modified: 2012-08-14
Thats basically what i need to know in a nutshell.....
these are the parameters
-The first digit can't be a zero
-The first 3 digits can't contain an 8 or 9
-the second set of 3 digits cant begin with a zero
-the second set of 3 digits cant be greater than 610
-The first digit of the last set of digits cant be a zero

(ultimately i need it written in java form)
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Question by:vsands
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9 Comments
 
LVL 37

Expert Comment

by:zzynx
ID: 12286275
What do you have already?
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LVL 37

Expert Comment

by:zzynx
ID: 12286292
We're not here to write a complete programs for you. (Lots of other sites exist for that)
We're here to help you with problems you might have when writing your program
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Expert Comment

by:zzynx
ID: 12286313
Use java.util.Random.nextInt() to generate the parts of your telephone number
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LVL 37

Accepted Solution

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zzynx earned 50 total points
ID: 12286387
This can give you an idea:

String digits[] = { "0", "1", "2", "3", "4", "5", "6", "7", "8", "9" };
StringBuffer telephoneNr = new StringBuffer();
Random rd = new Random();

// Generate first digit (which shouldn't be 0, 8 or 9)
String tmp;
do {
   tmp = digits[ rd.nextInt(8) ];
} while ( !tmp.equals("0") );
telephoneNr.append(tmp);

for (int i=1; i<=2; i++) { // Generate 2nd/3rd digit (which shouldn't be 8 or 9)
    do {
       tmp = digits[ rd.nextInt(10) ];
    } while ( !tmp.equals("0") );
    telephoneNr.append(tmp);
}

...
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LVL 37

Expert Comment

by:zzynx
ID: 12286400
Typo:

    tmp = digits[ rd.nextInt(10) ];

should be

    tmp = digits[ rd.nextInt(8) ];   // since 8 and 9 shouldn't be "picked"
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LVL 37

Expert Comment

by:zzynx
ID: 12286503
Or easier:

StringBuffer telephoneNr = new StringBuffer();
Random rd = new Random();

// Generate first part
String tmp;
do {
   tmp = "" + (100 + rd.nextInt(900));
} while ( tmp.indexOf("8")!=-1 || tmp.indexOf("9")!=-1 );
telephoneNr.append(tmp);

telephoneNr.append("-");

// Generate 2nd part
tmp = "" + (100 + rd.nextInt(511));
telephoneNr.append(tmp);

telephoneNr.append("-");

// Generate 3rd part
tmp = "" + (1000 + rd.nextInt(9000));
telephoneNr.append(tmp);

System.out.println( telephoneNr.toString() );
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LVL 2

Expert Comment

by:shah1d1698
ID: 12321679
Try this code.. Compile & run the program.


public class Application1
{

  String finalString = null;
  public void generateNumber()
  {
    int p1 = 0, p2 = 0, p3 = 0;
    String s1 = null, s2 = null, s3 = null;


    while(true)
    {
      p1 = (int) (Math.random() * 1000);
      String temp = "" + p1;
      int tempFlag = 0;
      for(int i = 0; i < temp.length();i ++)
      {
        if(temp.charAt(i) == '8' || temp.charAt(i) == '9')
        {
          tempFlag = 1;
        }
      }
      if(p1 > 100 && tempFlag == 0)
        break;
    }

    finalString = "" + p1;

    while(true)
    {
      p2 = (int) (Math.random() * 1000);
      if(p2 > 100 && p2 < 610)
        break;
    }

    finalString = finalString + "-" + p2;

    while(true)
    {
      p3 = (int) (Math.random() * 10000);
      if(p3 > 1000)
        break;
    }

    finalString = finalString + "-" + p3;

    System.out.println(finalString);

  }

  public static void main(String args[])
  {
    Application1 app = new Application1();
    for(int i = 0; i < 1000; i++) // this will generate 1000 numbers..
    {
      app.generateNumber();
    }
  }
}
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