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Numeric value of a string

Posted on 2004-10-12
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Last Modified: 2008-03-10
Hello,

I want to compare two strings for instance the first string holds the value "ABC" and the second string holds "ABD", But i want to find the numeric value of the string and then compare the two. I have used value of but it has not worked.

Cheers
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Question by:Cyart
  • 6
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  • +3
16 Comments
 
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Expert Comment

by:zzynx
ID: 12288082
String s1 = "ABC";
String s2 = "ABD";
Integer i1 =  Integer.valueOf(s1, 16);
Integer i2 =  Integer.valueOf(s2, 16);
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Author Comment

by:Cyart
ID: 12288119
What does the 16 represent?
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Expert Comment

by:zzynx
ID: 12288175
the radix to be used in interpreting the string
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LVL 37

Expert Comment

by:zzynx
ID: 12288188
I assumed that "ABC" stands for the hexadecimal value x0abc, right?
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Expert Comment

by:zzynx
ID: 12288203
>>What does the 16 represent?
>>the radix to be used in interpreting the string
See http://java.sun.com/j2se/1.4.2/docs/api/java/lang/Integer.html
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Author Comment

by:Cyart
ID: 12288257
No I want the deciamal value based on ascii i.e A = 65 so that ABC would give me 198.

Cheers
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Expert Comment

by:sudhakar_koundinya
ID: 12288314
int i=0;

for(int k=0;k<str.length();k++)
{
  i=i+str.chatAt(k);
}

int j=0;
for(int k1=0;k1<str1.length();k1++)
{
  j=j+str1.chatAt(k1);
}
//now u can compare j and i here
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Expert Comment

by:sudhakar_koundinya
ID: 12288317
where str="ABC";

where str1=="ABD";
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Assisted Solution

by:sciuriware
sciuriware earned 63 total points
ID: 12288323
String.compareTo(String otherString);  would serve you better then .....
;JOOP!
0
 
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Expert Comment

by:sudhakar_koundinya
ID: 12288335
String str="ABC";
String str1="ABD";

 int i=0;

for(int k=0;k<str.length();k++)
{
  i=i+str.chatAt(k);
}

int j=0;
for(int k1=0;k1<str1.length();k1++)
{
  j=j+str1.chatAt(k1);
}

System.err.println(i+" " +j);
0
 
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Expert Comment

by:sudhakar_koundinya
ID: 12288351
sciuriware

I just want to ask one question.  What is meaning of this ;JOOP!
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Accepted Solution

by:
Breadstick earned 62 total points
ID: 12289319
compareTo() in String might be all that you need to use.  It compares two strings lexicographically.  It will return 0 if the argument string is equal to this string; a value less than 0 if this string is lexicographically less than the string argument; and a value greater than 0 if this string is lexicographically greater than the string argument.  It doesn't just return -1, 0, and 1 though; the actual number that is returned is relational to the distance lexicographically that the two Strings are from each other.

This may be helpful:
http://java.sun.com/j2se/1.4.2/docs/api/java/lang/String.html#compareTo(java.lang.String)
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LVL 24

Expert Comment

by:sciuriware
ID: 12289410
Oh oh, here we go again:

Joop (dutch) == Johan (german) == John (british) == Johannes (Roman) == The one who was promised to us.

You're better off as the one who they wanted in the first place  ....................

;JOOP!
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Expert Comment

by:CEHJ
ID: 12289811
>>
for(int k=0;k<str.length();k++)
{
 i=i+str.chatAt(k);
}

>>

should be

for(int k=0;k<str.length();k++)
{
 i=i+str.charAt(k);
}

Maybe you were feeling talkative at the time sudhakar? ;-)



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Expert Comment

by:sudhakar_koundinya
ID: 12289849
:-))
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LVL 14

Expert Comment

by:sudhakar_koundinya
ID: 12289883
I am poor in using keyboard

as r and t are adjacent keys, I get type-o error

when keys are adjacent, I always face such  problems ;-)
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