Apothem
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Getting router IP
I'm trying to lookup my router IP but i don't know what/where to look, I don't know the maker/modle and all I have right now is a MAC ID. I'm trying to get my comp to be able to do some internet gaming again, but everything i try to connect to (including telnet) is 'actively refused'. I'm not entirely sure how to explain the situation so please, ask questions, because I'll prolly learn something from just you asking=D
Thanks for your time.
Thanks for your time.
www.whatismyip.com "should" show you your Internet side IP. Typically you could use that to figure your public side. If you know your local IP, I would run an IP scan on the same subnet. i.e. if your local IP is 192.168.32.45 with a subnet mask of 255.255.255.0 then ping every address from 192.168.32.2 to 192.168.32.254.
What kind of environment (school, work, home, etc), and how many other machines are on your side of the router?
What kind of environment (school, work, home, etc), and how many other machines are on your side of the router?
ASKER
Well lets see, I can get my internet IP easily, and when i use Cain & Abel to do the subnet scan, I get like 40+ systems, I checked my routing tables and they're all using a different submask than what's being assigned via DHCP in the ipconfig.... There's also a bunch of comps i can't resolve host names to... The environment, by the way, is a boarding school, with an unbelieveably unreliable network, The internet has been down for the last 2 days, and it just came back up and NOTHING works except Aol instant messenger and Internet explorer.... It's really wierd considering it wasnt like this beforehand...
ASKER
Ack, all of them are using a different mask, except 1, but then again, I don't know jack about the routing tables so I really shouldn't even have really mentioned it, I'll double the points tho if you can give a good description/explaination of what a routing table is along with the solution to this one.
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Well, technically, this is my school's network considering that I'm a boarding student, but anyway, I'm connected to a wireless router, the gateway, being 192.168.60.1, is universial on all computers.Which is why i came to the conclusion that maybe that ip isn't for every single AP on the campus. It appears the routers are no more than a forwarding point to the actual server where all the data is processed. Keep in mind that I can only do client side checks and it has been a real pain in the >>insert body part here<< trying to find out the littlest details about this network.
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Hmmm, well what's really funny about all this is the fact that AOL instant messenger works, which uses port 5190, and port 80 works, so yup, i think you're right.... I think i'm gonna strangle the network admin when i see him.... j/k =P Thanks everyone for your help!
See if you can run a traceroute. For instance, if you traceroute
At a command line, enter: tracert www.dnsstuff.com and you would get:
1 <1 ms <1 ms <1 ms vl242-c3-core-04.x.com [x.x.x.131]
2 <1 ms <1 ms <1 ms inside-c3-fw-01a.x.com [10.32.250.11]
3 <1 ms <1 ms <1 ms hsrp-x-border.x.com [x.x.x.1]
4 <1 ms <1 ms <1 ms f0-0-x-border-x.x.com [x.x.x.3]
5 5 ms 10 ms 5 ms t3-4-2-0.ar4.x.x.net [x.x.x.65]
6 5 ms 5 ms 5 ms 208.51.134.30
7 9 ms 5 ms 5 ms atl-core-02.inet.qwest.net
8 6 ms 5 ms 5 ms atl-core-01.inet.qwest.net
9 49 ms 65 ms 49 ms chi-core-02.inet.qwest.net
0 49 ms 49 ms 49 ms chi-core-01.inet.qwest.net
1 49 ms 49 ms 49 ms chi-edge-09.inet.qwest.net
2 56 ms 58 ms 57 ms 65.117.168.138
3 55 ms 56 ms 55 ms aggr-rtr02.eth4-6.sdf.xodi
4 55 ms 55 ms 55 ms kyle.ve23.sdf.xodiax.net [216.26.134.5]
5 56 ms 56 ms 57 ms host73.216.26.134.zirmed.c
6 57 ms 57 ms 57 ms www.dnsstuff.com [69.2.200.183]
Now, depending on how secure your network is, and if your network people block ICMP effectively, you could reverse it by going to http://www.dnsstuff.com and doing a traceroute back to your own network (use one of the first IP's in the traceroute above):
1 3 ms 9 ms 9 ms 216.26.134.2 [www.DNSstuff.com 1st hop] 62 UNITED STATES
2 34 ms 42 ms 53 ms 216.26.129.91 core-rtr02.ge-1-3-0.sdf.xo
3 3 ms 6 ms 39 ms 216.26.128.181 edge-rtr02.ge-0-3-0.sdf.xo
4 9 ms 14 ms 14 ms 65.117.168.137 chi-edge-09.inet.qwest.net
5 9 ms 12 ms 12 ms 205.171.20.125 chi-core-03.inet.qwest.net
6 11 ms 21 ms 14 ms 205.171.20.177 chi-core-02.inet.qwest.net
7 11 ms 14 ms 14 ms 205.171.205.34 cer-core-01.inet.qwest.net
8 10 ms 13 ms 13 ms 205.171.139.146 chp-brdr-01.inet.qwest.net
9 14 ms 9 ms 13 ms 208.50.13.249 [Missing reverse DNS entry] 245 UNITED STATES Unix: 11:24:13. 71
10 124 ms 161 ms 176 ms 67.17.68.230 so0-0-0-9953M.ar4.x.x.net.
11 * * *
12 * * *
13 * * *
14 * * *
[4 hops with no response; assuming we hit a firewall that blocks pings]
As you can see, we lock ours down ;) But the neat thing this does is give you IP addresses in bound and outbound and you can put them together.
Additionally, explore using "ping -r". At a command line, do a "ping /?"
HTH
PS - An easy way to test to see if ports are open, listening, and unblocked is to use telnet as was suggested - for instance, to test if you can get to https://www.experts-exchange.com over port 80, in a command line, type: telnet https://www.experts-exchange.com 80. When you get connected, type: get. All the html garbage you get tells you port 80 is open all the way to your destination.
To expand a bit (it's a pun) on the routing tables ...
Internet Protocol uses a hierarchial addressing scheme known as IP addresses. The subnet masks allow the routers and hosts to compare addresses and determine whether to change the layer 2 ethernet address or not.
Lets say you have host A, B, and C. A and B are on the same network. A wants to send the first packet of the day to B. A knows it's own IP address, its own subnet mask, and the destination IP address. First thing A will do is do a binary compare of its address and the destination using its subnet mask. This is a Binary AND. It will take it's 192.168.1.100 address and convert to binary to get 11000000.10101000.00000001
However, if it's sending to destination C and its address is 192.168.3.100 the binary AND would reveal that its on a different network because the 3 in binary is 00000011 and the 1 in binary (from the previous 3rd octet) is 1. So, it's DIFFERENT and it now knows it needs to be sent to the default gateway so it will issue an ARP to get the layer 2 MAC address of the default gateway and send the packet to the router.
Once the router gets it, it will compare the destination address to the IP addresses in its routing table and if it has an entry, will forward it out the appropriate interface.
Hope that makes some sense ...
At a command line, enter: tracert www.dnsstuff.com and you would get:
1 <1 ms <1 ms <1 ms vl242-c3-core-04.x.com [x.x.x.131]
2 <1 ms <1 ms <1 ms inside-c3-fw-01a.x.com [10.32.250.11]
3 <1 ms <1 ms <1 ms hsrp-x-border.x.com [x.x.x.1]
4 <1 ms <1 ms <1 ms f0-0-x-border-x.x.com [x.x.x.3]
5 5 ms 10 ms 5 ms t3-4-2-0.ar4.x.x.net [x.x.x.65]
6 5 ms 5 ms 5 ms 208.51.134.30
7 9 ms 5 ms 5 ms atl-core-02.inet.qwest.net
8 6 ms 5 ms 5 ms atl-core-01.inet.qwest.net
9 49 ms 65 ms 49 ms chi-core-02.inet.qwest.net
0 49 ms 49 ms 49 ms chi-core-01.inet.qwest.net
1 49 ms 49 ms 49 ms chi-edge-09.inet.qwest.net
2 56 ms 58 ms 57 ms 65.117.168.138
3 55 ms 56 ms 55 ms aggr-rtr02.eth4-6.sdf.xodi
4 55 ms 55 ms 55 ms kyle.ve23.sdf.xodiax.net [216.26.134.5]
5 56 ms 56 ms 57 ms host73.216.26.134.zirmed.c
6 57 ms 57 ms 57 ms www.dnsstuff.com [69.2.200.183]
Now, depending on how secure your network is, and if your network people block ICMP effectively, you could reverse it by going to http://www.dnsstuff.com and doing a traceroute back to your own network (use one of the first IP's in the traceroute above):
1 3 ms 9 ms 9 ms 216.26.134.2 [www.DNSstuff.com 1st hop] 62 UNITED STATES
2 34 ms 42 ms 53 ms 216.26.129.91 core-rtr02.ge-1-3-0.sdf.xo
3 3 ms 6 ms 39 ms 216.26.128.181 edge-rtr02.ge-0-3-0.sdf.xo
4 9 ms 14 ms 14 ms 65.117.168.137 chi-edge-09.inet.qwest.net
5 9 ms 12 ms 12 ms 205.171.20.125 chi-core-03.inet.qwest.net
6 11 ms 21 ms 14 ms 205.171.20.177 chi-core-02.inet.qwest.net
7 11 ms 14 ms 14 ms 205.171.205.34 cer-core-01.inet.qwest.net
8 10 ms 13 ms 13 ms 205.171.139.146 chp-brdr-01.inet.qwest.net
9 14 ms 9 ms 13 ms 208.50.13.249 [Missing reverse DNS entry] 245 UNITED STATES Unix: 11:24:13. 71
10 124 ms 161 ms 176 ms 67.17.68.230 so0-0-0-9953M.ar4.x.x.net.
11 * * *
12 * * *
13 * * *
14 * * *
[4 hops with no response; assuming we hit a firewall that blocks pings]
As you can see, we lock ours down ;) But the neat thing this does is give you IP addresses in bound and outbound and you can put them together.
Additionally, explore using "ping -r". At a command line, do a "ping /?"
HTH
PS - An easy way to test to see if ports are open, listening, and unblocked is to use telnet as was suggested - for instance, to test if you can get to https://www.experts-exchange.com over port 80, in a command line, type: telnet https://www.experts-exchange.com 80. When you get connected, type: get. All the html garbage you get tells you port 80 is open all the way to your destination.
To expand a bit (it's a pun) on the routing tables ...
Internet Protocol uses a hierarchial addressing scheme known as IP addresses. The subnet masks allow the routers and hosts to compare addresses and determine whether to change the layer 2 ethernet address or not.
Lets say you have host A, B, and C. A and B are on the same network. A wants to send the first packet of the day to B. A knows it's own IP address, its own subnet mask, and the destination IP address. First thing A will do is do a binary compare of its address and the destination using its subnet mask. This is a Binary AND. It will take it's 192.168.1.100 address and convert to binary to get 11000000.10101000.00000001
However, if it's sending to destination C and its address is 192.168.3.100 the binary AND would reveal that its on a different network because the 3 in binary is 00000011 and the 1 in binary (from the previous 3rd octet) is 1. So, it's DIFFERENT and it now knows it needs to be sent to the default gateway so it will issue an ARP to get the layer 2 MAC address of the default gateway and send the packet to the router.
Once the router gets it, it will compare the destination address to the IP addresses in its routing table and if it has an entry, will forward it out the appropriate interface.
Hope that makes some sense ...
ASKER