Link to home
Start Free TrialLog in
Avatar of Ken Selvia
Ken SelviaFlag for United States of America

asked on

How to find coordinates of intersection of a line and a circle

Hello experts,

I have a circle plotted in x,y coordinates.  The center is at (14,5) with a radius of 5.

I have a point (*) at (16,6).  I need a formula to determine the x,y coordinates where
a line intersects the circle (at ? below) if drawn from the center of the circle through the point *.

y
|                    
|             .
|         .      ?.
|               *    
|       .     @     .
|
|         .       .
|             .
|
+-------------------------x

The coordinates I gave are just an example, I need a formula to solve any center, radius and * point.

BTW: This is not a homework problem. If I had paid more attention in geometry though I would
proabably know how to do this.   This is not really a Java problem but I didn't know the
best forum to post it in.
SOLUTION
Avatar of Mick Barry
Mick Barry
Flag of Australia image

Link to home
membership
This solution is only available to members.
To access this solution, you must be a member of Experts Exchange.
Start Free Trial
Avatar of Ken Selvia

ASKER

I saw that (and had actually already looked at it) and the answer is probably there someplace but I need it spelled out.

Given the data I have:  The center point, another point inside the circle, where will a line drawn from the center throug the point cross the circle.
the equation is given on that page, which part is giving you problems?
The part where I find the equation on the page.
"gives the points of intersection as ..."
http://mathworld.wolfram.com/c1img3452.gif
ASKER CERTIFIED SOLUTION
Link to home
membership
This solution is only available to members.
To access this solution, you must be a member of Experts Exchange.
Start Free Trial
Yes I understand now. Thank you both very much.
Something like this?

class Circle
{

...
/**
 * Find the intersection of this circle with the line defined by point p1 & p2
public Point Intersect(Point p1, Point p2)
{
   int dx=p2a.x-p1.x;
   int dy=p2.y-p1.y;
   int dr=Math.sqrt(dx*dx+dy*dy);
   int D=p1.x*p2.y-p2.x*p1.y;
   int discriminant=this.radius*this.radius*dr*dr-D*D;
   if (discriminant<0)
      return null;  //No intersection;
   else if (discriminant==0)
      ;//Tangant line there is only ONE intersection
    else if (discriminant>0)
      ;//The line intersects at TWO points

   //Compute intersection for ONE point (to compute intersection at OTHER point change + to a -)
   int x=(D*dy+Math.sgn(dy)*dx*Math.sqrt(discriminant))/(dr*dr);
   int y=(-D*dx+Math.abs(dy)*Math.sqrt(discriminant))/(dr*dr);
   return new Point(x,y);
}
Thanks for accepting