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Date processing in VB

Posted on 2004-10-27
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Last Modified: 2010-04-17
Given a date in mm/dd/yyyy format. how can i find the no of days on that month.  is there any built in functions available in VB...??
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Question by:bushairkp
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    by:ADSaunders
    Hi bushairkp,
    If it is a date type, then the difference in days between that date and a month hence will give you the answer:
    Days = datediff("d", <givendate>, dateadd("m",1, <givendate>))

    Regards .. Alan
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    by:ADSaunders
    bushairkp,
    If it's actually a date type, the format doesn't matter
    .. Alan
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    Author Comment

    by:bushairkp
    i am telling you ...i want to find the no of days of a month.
    i mean ..suppose our function name is xxxxx
    if i passed a value to (01/01/2002) then it should return 31 , and if i passed a value 02/15/2002(feb) then it should return 28. if the value is 02/15/2004 (feb-leap year) it should return 29.....

    do you know any functions intented for that ...??
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    Accepted Solution

    by:
    Hi,
    The above statement will do that.
    Given 01/01/2002 as <givendate>:
    dim Givendate as date, NextMonth as date
    Givendate = cDate("01/01/2002")
    NextMonth = dateadd("m",1, Givendate) will give a date that will format as either 01/02/2002 or 02/01/2002 (depending on US or GB locale)
    datediff("d",Givendate,NextMonth) (GB) will give the number of days between 01/01/2002 and 02/01/2002. i.e. the number of days in January 2002.

    .. Alan
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    Expert Comment

    by:Rick_Townsend
    Here's an alternative (if you're looking for other options.)  The following code uses the DateSerial function:

        Format$(Day(DateSerial(Year(givenDate), month(givenDate) + 1, 0)))

    (It assumes that givenDate is a Date type.  Use cDate(dateString) as specified by ADSaunders if you need to do a String to Date conversion.)
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