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Another DC question.

Posted on 2004-10-28
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Last Modified: 2010-05-02
Hi!

I'm going crazy with these DC's (Device Context). As soon as I think I understand how it works, I found out that I'm wrong.

So, please can someone explain:
 - how DC's work?
 - how to create my own DC which will hold the picture loaded in PictureBox control, so later I can work with this DC the same as if I would work with PictureBox'es DC.

This is what I'm trying but it just won't work. Why?
 - create two pictureboxes and assign some pictures to them
 - create two command buttons
 - paste this code:
'----------------------------------------------------------------
Private Declare Function BitBlt Lib "gdi32" (ByVal hDestDC As Long, ByVal x As Long, ByVal y As Long, ByVal nWidth As Long, ByVal nHeight As Long, ByVal hSrcDC As Long, ByVal xSrc As Long, ByVal ySrc As Long, ByVal dwRop As Long) As Long
Private Declare Function CreateCompatibleBitmap Lib "gdi32" (ByVal hdc As Long, ByVal nWidth As Long, ByVal nHeight As Long) As Long
Private Declare Function CreateCompatibleDC Lib "gdi32" (ByVal hdc As Long) As Long
Private Declare Function SelectObject Lib "gdi32" (ByVal hdc As Long, ByVal hObject As Long) As Long

Private Const SRCCOPY = &HCC0020

Dim NewDC As Long
Dim NewBMP As Long

Private Sub Command1_Click()
    BitBlt Picture2.hdc, 0, 0, 15, 23, Picture1.hdc, 0, 0, SRCCOPY
End Sub

Private Sub Command2_Click()
    NewDC = CreateCompatibleDC(Picture1.hdc)
    NewDC = CreateCompatibleBitmap(Picture1.Picture.Handle, 15, 23)
    NewBMP = SelectObject(NewDC, Picture1.Picture.Handle)

    BitBlt NewDC, 0, 0, 15, 23, Picture1.hdc, 0, 0, SRCCOPY
    BitBlt Picture2.hdc, 0, 0, 15, 23, NewDC, 0, 0, SRCCOPY
End Sub

Private Sub Form_Load()
    Command1.Caption = "Working"
    Command2.Caption = "Not working! Why?"
End Sub
'--------------------------------------------------------------------

Thanks!
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Question by:dbrckovi
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3 Comments
 
LVL 6

Accepted Solution

by:
Amritpal Singh earned 2000 total points
ID: 12431560
hi ,
have a look at the article at this link
http://www.officecomputertraining.com/vbtutorial/tutpages/page44.asp
0
 
LVL 11

Author Comment

by:dbrckovi
ID: 12431842
Thank you.

I realized what was the problem thanks to your link. My way of thinking was correct, but I didn't notice few errors in the syntax.
0
 
LVL 6

Expert Comment

by:Amritpal Singh
ID: 12431865
welcome :))
n e time
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