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# Function procedure

Posted on 2004-10-28
Medium Priority
234 Views
On this one , I want to do 2 things
1) write a function procedure that receives the value stored in an integer variable named intNumber. The procedure, named DivideNumber, should divide the integer by 2, and then return the result (which may contain a decimal place)
2)write an appropriate statement to call the Dividenumber function created above.

Any help would be greatly appreciated... thx.
0
Question by:skathari
• 3
• 3
• 2
• +3

LVL 2

Expert Comment

ID: 12441310
Here you have one solution:

Private Function DivideNumber(ByVal Number As Integer) As Double
Dim result As Double

result = (Number / 2)

Return result
End Function

to call the functio you must do the following:

Dim number As Double
Dim intNumber As Integer

intNumber = 2
number = DivideNumber(intNumber)

That's it.
0

LVL 19

Expert Comment

ID: 12441325
This sounds like homework and experts answering those questions can get suspended..  you better give it a try at least, as it wont be too difficult for you.... have some problem ask us...
0

Author Comment

ID: 12441351
its not homework.... these are just practice for us. What I am trying to get, is an example simple just like this, and then try to remember it and see how they do it.
In other words, its optional for me to practice... practice gets you better.
0

LVL 27

Expert Comment

ID: 12443226
FYI .....
Hi,

Here is where I found good examples for working in VB.Net

0

LVL 44

Expert Comment

ID: 12443306
in VB.NET this can be wriiten as:

Private Function DivideNumber(ByVal Number As Integer) As Double

return Number / 2

End Function

AW
0

LVL 44

Accepted Solution

Arthur_Wood earned 400 total points
ID: 12443319
then to use this function:

Private Sub UseFunction()

Dim intTest as Integer = 100
Dim dblAnswer as Double = DivideNumber(intTest)

MessageBox.Show("DivideNumber(" & intTest & ") = " dblAnswer)

End Sub

Private Function DivideNumber(ByVal Number As Integer) As Double

return Number / 2

End Function
0

LVL 44

Expert Comment

ID: 12443324
oops, minor type:

MessageBox.Show("DivideNumber(" & intTest & ") = " & dblAnswer)
0

Author Comment

ID: 12447695
but, dont we have to add a button?
0

LVL 86

Expert Comment

ID: 12448931
Hi skathari,

You didn't ask for a GUI on top of the function.  You simply asked for a function to do X.  The button code is not part of the function.

At any rate, it sounds like you need to see some complete working code...

0

LVL 86

Assisted Solution

Mike Tomlinson earned 400 total points
ID: 12448967
(hit the submit button on accident)

Here is a very simple app that uses the function provided by Arthur_Wood:

Public Class Form1
Inherits System.Windows.Forms.Form

#Region " Windows Form Designer generated code "

Public Sub New()
MyBase.New()

'This call is required by the Windows Form Designer.
InitializeComponent()

'Add any initialization after the InitializeComponent() call

End Sub

'Form overrides dispose to clean up the component list.
Protected Overloads Overrides Sub Dispose(ByVal disposing As Boolean)
If disposing Then
If Not (components Is Nothing) Then
components.Dispose()
End If
End If
MyBase.Dispose(disposing)
End Sub

'Required by the Windows Form Designer
Private components As System.ComponentModel.IContainer

'NOTE: The following procedure is required by the Windows Form Designer
'It can be modified using the Windows Form Designer.
'Do not modify it using the code editor.
Friend WithEvents TextBox1 As System.Windows.Forms.TextBox
Friend WithEvents Button1 As System.Windows.Forms.Button
Friend WithEvents Label1 As System.Windows.Forms.Label
<System.Diagnostics.DebuggerStepThrough()> Private Sub InitializeComponent()
Me.TextBox1 = New System.Windows.Forms.TextBox
Me.Button1 = New System.Windows.Forms.Button
Me.Label1 = New System.Windows.Forms.Label
Me.SuspendLayout()
'
'TextBox1
'
Me.TextBox1.Location = New System.Drawing.Point(8, 8)
Me.TextBox1.Name = "TextBox1"
Me.TextBox1.Size = New System.Drawing.Size(128, 20)
Me.TextBox1.TabIndex = 0
Me.TextBox1.Text = "Enter an Integer Here"
'
'Button1
'
Me.Button1.Location = New System.Drawing.Point(144, 8)
Me.Button1.Name = "Button1"
Me.Button1.Size = New System.Drawing.Size(96, 24)
Me.Button1.TabIndex = 1
Me.Button1.Text = "DivideNumber()"
'
'Label1
'
Me.Label1.BorderStyle = System.Windows.Forms.BorderStyle.FixedSingle
Me.Label1.Location = New System.Drawing.Point(248, 8)
Me.Label1.Name = "Label1"
Me.Label1.Size = New System.Drawing.Size(144, 24)
Me.Label1.TabIndex = 2
Me.Label1.Text = "Result"
Me.Label1.TextAlign = System.Drawing.ContentAlignment.MiddleCenter
'
'Form1
'
Me.AutoScaleBaseSize = New System.Drawing.Size(5, 13)
Me.ClientSize = New System.Drawing.Size(400, 38)
Me.Name = "Form1"
Me.Text = "Example of Divide by 2 Function"
Me.ResumeLayout(False)

End Sub

#End Region

Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim value As Integer
Try
value = Integer.Parse(TextBox1.Text)
Label1.Text = DivideNumber(value).ToString
Catch ex As Exception
MessageBox.Show(ex.Message, "Error", MessageBoxButtons.OK, MessageBoxIcon.Error)
End Try
End Sub

Private Function DivideNumber(ByVal Number As Integer) As Double
Return Number / 2
End Function

End Class
0

Author Comment

ID: 12450451
thank you guys... it is working perfect!!!
0

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