• C

how to copy from uint to char[] ?

i have a problem here...........

in my program, i have

char OutputString[20];
uint8_t Message_Digest[20];


then i have
for(i = 0; i < 20 ; ++i)
     printf("%02X ", Message_Digest[i]);
which gives me what i wan. but how do i copy the output into the OutputString ? so that OutputString contains all the

printf("%02X ", Message_Digest[i]); from i=0 to 19...
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You need to do something like this:
1) OutputString should be much bigger than 20
2) And...
char OutputString[62];
int i;
int outlen = 0;
for(i=0;( i < 20 );i++) {
  outlen += sprintf( &(OutputString[outlen]), "%02X ", Message_Digest[i]);

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harsherAuthor Commented:
thanx very much... ur da man!!!!!!!!!
You are welcome
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