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C++ offsetof macro

Posted on 2004-11-19
Medium Priority
Last Modified: 2012-05-05
Can someone tell me why the offsetof macro is not returning the correct result? The offset of c is clearly 2 bytes, yet Visual C++ 6.0 returns a value of 4 for the offset. Thanks.

#include "stdafx.h"
#include <windows.h>
#include <stddef.h>
struct a
      short b;  //0x00
      long c;   //0x02

int main(int argc, char* argv[])
      DWORD d = offsetof(a,c);  //0x04
      return 0;

Question by:jweston1
  • 2
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LVL 13

Expert Comment

ID: 12622951
Due to get variables on predefined memory locations there might be additional bytes added to the struct. For performance reasons variables of length 4 should be on memory locations with the last two bits 0. Try the example again with
struct a {
  short b1;
  short b2;
  long c;

offsetof (a, b2) should return 2.
LVL 48

Expert Comment

ID: 12622956
This happens because structure members are aligned to 32-bits boundary.
LVL 13

Accepted Solution

SteH earned 200 total points
ID: 12622957
And have a look at the documentation of
#pragma pack (n)
to see how to change this behaviour.
LVL 48

Assisted Solution

AlexFM earned 200 total points
ID: 12622962
See /Zp compiler option (Struct Member Alignment).

Author Comment

ID: 12622977
It seems the compiler is allocating a long for the short even though I've specified it as short. Maybe this is for alignment or something.

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