find oldest file

I have a directory with about 20 sub directories in it that has a thousands of files in them all together, I need a script to find what is the oldest file and show date and time created in which ever one of these sub directories.

EX

/mail/queues/(dir's 1-20)

thanks,

bt707Asked:
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rj2Commented:
use File::Find;

$dir='/mail/queues';

find(\&wanted_files, $dir);

print "The oldest file is $oldestname, last modified $oldestdays days ago\n";

sub wanted_files{
      if(-f $_) {
            $File::Find::dir=~m![/\\]([^/\\]+)$!;
            $topdir=$1;
            if($topdir >= 1 && $topdir <= 20) {
                  #print "Checking dir $File::Find::dir ($topdir)\n";
                  $days=-M $File::Find::name;
                  if($days > $oldest) {
                        $oldestdays=$days;
                        $oldestname=$File::Find::name;
                  }            
            } else {
                  #print "Not checking dir $File::Find::dir ($topdir)\n";
            }      
      }
}
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roee_fCommented:
#!/usr/bin/perl
use strict;
use warnings;
use File::Find;

@ARGV = qw(".") unless @ARGV;
my $oldestName = "";
my $oldestDate = 0;

sub process_file {
      return unless -f $_ && -M $_ > $oldestDate;
    $oldestDate = -M $_ ;
    $oldestName = $File::Find::name;
}

find(\&process_file, ".");

my $age = (stat($oldestName))[9];
print "Oldest file is $oldestName. Changed in ", scalar(localtime($age)), "\n";
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ozoCommented:
If you want to restrict the find to /mail/queues/{1..20} out of possiblly other /mail/queues/* sub directories, other you can use
find(\&process_file, map{"/mail/queues/$_"}1..20);
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bt707Author Commented:
That one worked great I just didn't get back to accept it, others looks good but the first one worked and didn't get to try the others.


Thanks,
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