AWK command & SORT

I have a command I use like this:

awk ' /refused/ {print $6, $7, $16, $17,$18}' log_file1 | sort | uniq -c

It works fine but when it prints out each line with the number of times that line occured in the file I want it to do a sort on the number of times it occured in the file.
I want the ones that occured in the file the most to be on top and sorted desending down, I wanted to pipe this command back to sort but can't find a way to sort
the number of occurances, I'm sure this can be done but can't find a way to do it.

Thanks,
bt707Asked:
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gripeCommented:
Just append:

awk ' /refused/ {print $6, $7, $16, $17,$18}' log_file1 | sort | uniq -c | sort -nr
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wesly_chenCommented:
Put -nr for sort:
awk ' /refused/ {print $6, $7, $16, $17,$18}' log_file1 | sort -nr | uniq -c

Wesly
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wesly_chenCommented:
Oops, gripe just got it.

Wesly
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bt707Author Commented:
Thanks gripe, that's what i was looking for.

Thanks again
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