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JDOM - compare 2 Element's

Hi there,

does anyone use the JDOM api?
I want to compare 2 different elements to see if they are the same.
- same = same number of children; children have the same number of children; the element and attributes of each child have the same value!!

Im guessing this is a recursive nightmare (especially considering that the itteration of element 1 must always be at same point as that of element 2).
So has it been done before!!

Cheers,
Cathal.

ASKER CERTIFIED SOLUTION

lhankins

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CEHJ

Yes, i think you'll have to do this 'manually' and recursively

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CEHJ

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sudhakar_koundinya

Not tested thoroughly, but might give u some idea

package org.prithvi.test;

import java.io.*;
import org.jdom.*;
import org.jdom.input.*;
import org.jdom.output.*;
import java.util.*;

public class JDomTest {
public JDomTest() {
}

public static void main(String[] args) {
try {
Document d = new SAXBuilder().build(new File("c:/1.xml"));
Document d1 = new SAXBuilder().build(new File("c:/11.xml"));

Element e = d.getRootElement();
Element e1 = d1.getRootElement();
check(e, e1);
}
catch (Exception e) {
e.printStackTrace();
}
}

public static boolean check(Element e, Element e1) {
List l = e.getChildren();
List l1 = e1.getChildren();
if (l.size() != l1.size()) {
return false;
}

boolean b = true;
b = e.getName().equals(e1.getName());
if (b) {
b = e.getValue().equals(e1.getValue());
if (!b) {
return false;
}
}
else {
return false;
}
for (int i = 0; i < l.size(); i++) {
Element e2 = (Element) l.get(i);
Element e3 = (Element) l1.get(i);

List att1 = e2.getAttributes();
List att2 = e3.getAttributes();
if (att1.size() != att2.size()) {
return false;
}
for (int j = 0; j < att1.size(); j++) {
Attribute at1 = (Attribute) att1.get(j);
Attribute at2 = (Attribute) att2.get(j);
b = at1.getValue().equals(at2.getValue());
if (b) {
b = at1.getName().equals(at2.getName());
if (!b) {
return false;
}
}
else {
return false;
}
}
if (e2.getText().equals(e3.getText())) {
b = check(e2, e3);
if (!b) {
return false;
}
}
else {
return false;
}

}
return true;

}

}

sudhakar_koundinya

You can test like this

if (check(e, e1)) {
System.err.println("Same Xml files");
}
else {
System.err.println("Different Xml files");
}

sudhakar_koundinya

CEHJ,

your's is much simpler than my code. Easy to understand and no recursion. Good One ;-)

CEHJ

>>your's is much simpler than my code. Easy to understand and no recursion. Good One ;-)

lhankins' idea ;-)

cathalmchale

ASKER

Thanks for your posts, this works very nicely ;-)

CEHJ

:-)