Syntax Question

What is the meaning of the line below:

     my $hh=join('+',sort {$a <=> $b} @l) ; $f[$t]=$hh ;

Also could you explain :

  foreach my $m (split(/\+/,$f[$t])) {
              push @cl,$mbd[$m] ;
           }
Cosine_ConsultantsAsked:
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kanduraCommented:
have you considered reading the documentation that comes with Perl?
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gripeCommented:
What algorithm was the file encrypted with?

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gripeCommented:
Argh, damn quickpost. :)

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sstoukCommented:
This portion:

my $hh=join('+',sort {$a <=> $b} @l) ;  $f[$t]=$hh ;


Array @l contains elements that are sorted from lowest to highest value and joined with the '+' sign
The result is a scalar, assigned to variable $hh, which is in turn assigned to the element $t or the array @f;

For example,
let's say
@l = ('222','333','111');
After:
$hh=join('+',sort {$a <=> $b} @l) ;  

$hh will be equal to  '1+2+3'
and if We have an array with elements
@f = ('first','second','third');
and $t = 1, then after
$f[$t]=$hh ;

$f[$t] will be '1+2+3';
And
@f will be equal to ('first','1+2+3','third');

##########################################################
The Next process takes the value
'1+2+3' and splits it in places where the character '+' is into elements.
It loops though the elements, assigning each current value to variable $m

foreach my $m (split(/\+/,$f[$t]))
{
push @cl,$mbd[$m] ;
}

For each iteration, variable $m will take a value of  '1', then '2', then '3' because we split the Scalar into these elements.

There is an array @mbd with some elements in it;
If For Example
@mbd = ('First','Second','Third','Fourth');

Then element $mbd[1] is "Second";
Element $mbd[2] is "Thurd"; etc.

So when we loop though the splitted elements of the scalar variable $f[$t] (which is just one element of an array @f) we get
$mbd[1] then $mbd[2]  then $mbd[3]  because $m = 1, then $m = 2, then $m = 3
Command 'push'; pushes the values of the array $mbd into a new array - @cl

After the loop finishes, @cl = ('Second','Third','Fourth');

###################################################################

There is nothing more to it.





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sstoukCommented:
Change
#################
For example,
let's say
@l = ('222','333','111');
#################
To:
#################
For example,
let's say
@l = ('2','3','1');
#################
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roee_fCommented:
a. as some has pointed, you're gonna have to buy a good Perl book (I recommend on "Learning Perl" if you're new to programming and or perl. Also, "Programming Perl". Both of them are 3rd edtioins from O'reilly.

b. Here is a sample code for your first question:
my @l = (4,2,8,4,10);
my $hh=join('+',sort {$a <=> $b} @l) ;
print "$hh\n";

sort {$a <=> $b} @l

sort function gets as parameters
a. sorting function (which defaults to asciibetically)
b. a list to sort
Here the sorting function is to sort numerically. This is the meaning of the "Spaceship" operator (<=>). $a and $b are special variables to sort, which tells it, in that case to sort in ascending order.

join gets as parameters
a. a joiner character
b. a list to join.
It returns as result the string.

Run this code to see what I mean.

$f[$t]=$hh ;

This is a simple assignment of the result to the $t element in @f array.

c.
foreach my $m (split(/\+/,$f[$t])) {
              push @cl,$mbd[$m] ;
           }

split(/\+/,$f[$t])

split is the reverse of join.
It gets
a. the character to split according to
b. the string to split
It returns a list.

This loop iterates on each element of this list, (which seems like a list of array's indices) in each iteration pushing the result to @cl array.
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ozoCommented:
c. could also be
push @cl,@mbd[split(/\+/,$f[$t]];
or, combining the two:
push @cl,@mbd[sort {$a <=> $b} @l];

see
perldoc -f sort
perldoc -f join
perldoc -f split
perldoc -f push
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