AWK and Sort by field

I have  a large log file that has 18 fields in it,

Ex:

22-Nov-2004 01:35:54.44 tcp_in              Q 5 jcfaxhgibblyu@yyhmail.com rfc822;find@com find@com /mail/06/queue/tcp_in/002/ZR0I7Z00AF6W3UDF.00 <FYCQIMPNYZQGGRYOZKLQHMEM@wonet.com>  TCP active open: Failed connect()    Error: Connection refused


I want to forget about the fist 6 fields and do a sort by using the 7th field then print out how many times that the 7th field was duplicated in how many lines.


Thanks,






bt707Asked:
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gripeCommented:
awk '{print $7}' your.log | sort | uniq -c
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bt707Author Commented:

Thanks that worked, just what I wanted, had it almost right but that one little screw up always ruins everything,

One more question before I close this,

Is there a way to do this sort of field 7 and tell it to ignore a certain part of the value,  

Ex:

field 7 =   user@domain.com


I want to Ignore anything up to the @ and then sort with the remaining part of the feild

Ex:

user@domain.com   ignore the user  and then sort all of the field 7's user the rest  @domain.com

Thanks,
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wesly_chenCommented:
awk '{print $7}' your.log |awk -F@ '{print $2}' | sort | uniq -c

Wesly
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wesly_chenCommented:
awk '{print $7}' your.log |awk -F@ '{print "@"$2}' | sort | uniq -c
                                                            ^^^

Wesly
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gripeCommented:
awk -F@ '{print $3}' foo.txt | sort | uniq -c
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bt707Author Commented:
Thanks gripe, that's what I needed, other answers looked good but you had already answered my original question, that's for the additional fix.


Thanks again,
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