XSLT 2.0 syntax within concat()
Posted on 2005-02-25
I am trying to pass a value into concat() and am a bit lost. The code:
<xsl:for-each-group select="/Reports/Report" group-by="@type">
Where I have written "**HERE**" I want the value of 'current-group()/Rpt_Code' which is at the same depth level as Rpt_Title.
TIA, Ken Smith