Converting from CString to String and char array string needed to yield the same string type

I have converted a couple of char array to string like this:
code:
char username_in[20];
char password_in[20];
std::string a((char*) username_in);
std::string b((char*) password_in);   //this part compiled fine

I have convereted a couple of CString to String like this:
code:
DDX_CBString(pDX, IDC_Username, L_username);  
DDX_CBString(pDX, IDC_Password, L_password);
std::string u1((LPCTSTR)L_username);
std::string p1((LPCTSTR)L_password);   //this part compiled fine

But when I try to do a string compare like this:
int sameU = strcmp(a,u1);
int sameP = strcmp(b,p1);

it gives me the error that the two types i'm trying to pass into the strcmp are not the same.
I'm confused because I thought i had changed both of the types to strings so that i can compare them.
So there is probably something wrong with my conversion but I'm not sure what...

This is the error I'm getting:
{
error C2664: 'strcmp' : cannot convert parameter 1 from 'class std::basic_string<char,struct std::char_traits<char>,class std::allocator<char> >' to 'const char *'
        No user-defined-conversion operator available that can perform this conversion, or the operator cannot be called
}
chinese_bunnyAsked:
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AlexFMCommented:
int sameU = strcmp(a.c_str(),u1);
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AxterCommented:
Hi chinese_bunny,
You need to use the c_str member function.
Example:

int sameU = strcmp(a.c_str(),u1.c_str());
int sameP = strcmp(b.c_str(),p1.c_str());

The .c_str() method returns the constant char* pointer that the C-Style string functions are looking for.
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chinese_bunnyAuthor Commented:
oh my gosh! thank you very much to both of you.  it works like a charm now. 0 errors! <33333
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