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Can't output numerical values to a file

I am trying to output the values of an array of integer variables to a file using the following code:

ofstream outf;
outf.open(argv[4],ios::out|ios::binary);
if(outf){

      long numRecords;
      char recordType[2200];
      int val[13][2200];

recordType[1999] = 'D';
val[0][0] = 251658240;
val[1][0] = 2;
val[2][0] = 2;
val[3][0] = 0;
val[4][0] = 0;

//there are additional values is this area

recordType[1999] = 'D';
val[0][1999] = 251658240;
val[1][1999] = 2;
val[2][1999] = 2;
val[3][1999] = 0;
val[4][1999] = 0;
val[5][1999] = -2000;
val[6][1999] = -4000;
val[7][1999] = -6000;
val[8][1999] = -8000;
val[9][1999] = -10000;
val[10][1999] = -12000;
val[11][1999] = -14000;
val[12][1999] = -16000;
numRecords = 2000;

      for(long i = 0; i < numRecords; i++){
            outf << recordType[i] << val[0][i];
            for(int j = 1; j < 13; j++)
                  outf << val[j][i];
      }
      outf.close();
}

But the output file ends up containing the ascii characters corresponding to these values rather than their numeric binary values. What am I doing wrong!!!

greggpb

dont use the ios::binary flag

ASKER CERTIFIED SOLUTION

jkr

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DaveStahl

ASKER

Thanks alot! Actually in order to work this needed to be revised slightly to:

char* valOut = new char();
for(long i = 0; i < numRecords; i++){
outf << recordType[i];
for(int j = 0; j < 13; j++){
valOut = (char*)&val[j][i];
outf.write(valOut, sizeof(int));
}
}

Using (char*)val[i][j] saved the VALUE at val[i][j] as a pointer which caused an access violation runtime error. &val[i][j] gave the right value. Also I found that in order to get it to work I needed to allocate memory for the char* with the new operator. Just coding outf.write((char*)&val[i][j],sizeof(int)); also made it crash. But definitely thanks for pointing me in the right direction. I was starting to go nuts trying to figure this out.

jkr

You're most welcome :o)