Can't output numerical values to a file

Posted on 2005-03-15
Medium Priority
Last Modified: 2010-04-01
I am trying to output the values of an array of integer variables to a file using the following code:

ofstream outf;

      long numRecords;
      char recordType[2200];
      int val[13][2200];

               recordType[1999] = 'D';
               val[0][0] = 251658240;
               val[1][0] = 2;
               val[2][0] = 2;
               val[3][0] = 0;
               val[4][0] = 0;

               //there are additional values is this area

               recordType[1999] = 'D';
               val[0][1999] = 251658240;
               val[1][1999] = 2;
               val[2][1999] = 2;
               val[3][1999] = 0;
               val[4][1999] = 0;
               val[5][1999] = -2000;
               val[6][1999] = -4000;
               val[7][1999] = -6000;
               val[8][1999] = -8000;
               val[9][1999] = -10000;
               val[10][1999] = -12000;
               val[11][1999] = -14000;
               val[12][1999] = -16000;
               numRecords = 2000;

      for(long i = 0; i < numRecords; i++){
            outf << recordType[i] << val[0][i];
            for(int j = 1; j < 13;  j++)
                  outf << val[j][i];

But the output file ends up containing the ascii characters corresponding to these values rather than their numeric binary values.  What am I doing wrong!!!
Question by:DaveStahl
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Expert Comment

ID: 13544621
dont use the ios::binary flag
LVL 86

Accepted Solution

jkr earned 750 total points
ID: 13544655
If you want to use ofstream to write binary data, you should use 'write()' instead of teh overloaded operators, e.g.

     for(long i = 0; i < numRecords; i++){
         outf << recordType[i];
         outf.write( (char*)val[0][i], sizeof(int));
         for(int j = 1; j < 13;  j++)
              outf.write( (char*)val[j][i], sizeof(int));

Author Comment

ID: 13546683
Thanks alot!  Actually in order to work this needed to be revised slightly to:

char* valOut = new char();
for(long i = 0; i < numRecords; i++){
     outf << recordType[i];
     for(int j = 0; j < 13; j++){
         valOut = (char*)&val[j][i];
         outf.write(valOut, sizeof(int));

Using (char*)val[i][j] saved the VALUE at val[i][j] as a pointer which caused an access violation runtime error.  &val[i][j] gave the right value.  Also I found that in order to get it to work I needed to allocate memory for the char* with the new operator.  Just coding outf.write((char*)&val[i][j],sizeof(int)); also made it crash.  But definitely thanks for pointing me in the right direction.  I was starting to go nuts trying to figure this out.
LVL 86

Expert Comment

ID: 13546698
You're most welcome :o)

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