RegExp with crlf?


TestString = "[quote=Blah]Test" & vbCrLf & "Test[/quote]"

Set r = New RegExp
r.pattern = "\[QUOTE=(.*?)\](.*?)\[/QUOTE\]" = true
r.ignorecase = True
tmpRet = TestString

  RunRegExp = tmpRet
  tmpRet = r.replace(tmpRet, "<table border=""0"" width=""90%"" align=""center""><tr><td>&nbsp;<b>Quote </b>&nbsp;from $1</td></tr><tr><td><div class=""quote"">$2</div></td></tr></table>")
Loop Until RunRegExp = tmpRet

Set r = Nothing

Response.Write RunRegExp


so the pattern as you can see is:"\[QUOTE=(.*?)\](.*?)\[/QUOTE\]"
and if I have a crlf in the string it does not work ... what do I have to change the pattern to, to make this work?
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The dot matches any character, except "\n".

I write it from memory (can't test just now), but the following may work...

Try replacing every dot in yout regexp with (.|\n) :

Or, even better, use a non capturing group (?:.|\n), so it won't interfere with what you already capture :

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ThaSmartUnoAuthor Commented:
now what would be different using the second one?

because they both work ... (i could have sworn i tried the first one, probably used []'s instead of ()'s)  
The syntax (xxx) means a capturing match : everything between the parenthesis will be captured by the regexp engine, so you can use it later in the Matches collection or in a replacement.

The syntax (?:xxx) means a non capturing match : the parenthesis are just used to group something (. and \n in our case).

A non capturing match is more efficient (the engine do not need to store anything)

And least, as your pattern already contain capturing matches, I thought it would be best to not change the order of your captures :

In your original pattern : \[QUOTE=(.*?)\](.*?)\[/QUOTE\]
capture #1=what follow "="
capture #2=what is between ] and [

with the first syntax I proposed, capture #2 would become capture #3 or #4, with the second one, their order is unchanged.

so, use the second one : no change in the order and more efficient.
ThaSmartUnoAuthor Commented:
Oh i see ... thank you
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