naimead12
asked on
perror()+invalid argument
Greetings to the forum,
I have a relatively simple problem that i don't know how to solve anymore.I am trying to open a file for writing using the fopen function but every time i have the same perror message:
invalid argument
The problem is that the file has already been started to be writen and after about 800kb this message appears.
I thought that the message means about the flag i use,but just in case i have been using many flags:a+,w+,wb+,r+,w and so on.
The file is a simple ASCII file
Any ideas to this problem please?
I have a relatively simple problem that i don't know how to solve anymore.I am trying to open a file for writing using the fopen function but every time i have the same perror message:
invalid argument
The problem is that the file has already been started to be writen and after about 800kb this message appears.
I thought that the message means about the flag i use,but just in case i have been using many flags:a+,w+,wb+,r+,w and so on.
The file is a simple ASCII file
Any ideas to this problem please?
ASKER
I am using windows 98.Here you are some code:
if ((stream1 = fopen("infile2.txt","w+")) == NULL) {
perror("the reason why");
printf("Error cannot open file 'infile2.txt' for writing...\n");
exit(0);
}
m = s->m;
s = global_s;
f = s->f;
for (y=0;y<m->ny;y++)
{
for (x=0;x<m->nx;x++)
{
for (z=0;z<m->nz;z++)
{
mx = f->mx[y][pos];
fprintf(stream1, "mx=%11.3e\n", mx);
my = f->my[y][pos];
fprintf(stream1, "my=%11.3e\n", my);
mz = f->mz[y][pos];
fprintf(stream1, "mz=%11.3e\n", mz);
}
}
}
//Although It starts writing to the infile2.txt about 800kb i have the error invalid argument
if ((stream1 = fopen("infile2.txt","w+"))
perror("the reason why");
printf("Error cannot open file 'infile2.txt' for writing...\n");
exit(0);
}
m = s->m;
s = global_s;
f = s->f;
for (y=0;y<m->ny;y++)
{
for (x=0;x<m->nx;x++)
{
for (z=0;z<m->nz;z++)
{
mx = f->mx[y][pos];
fprintf(stream1, "mx=%11.3e\n", mx);
my = f->my[y][pos];
fprintf(stream1, "my=%11.3e\n", my);
mz = f->mz[y][pos];
fprintf(stream1, "mz=%11.3e\n", mz);
}
}
}
//Although It starts writing to the infile2.txt about 800kb i have the error invalid argument
Is it embedded within a loop .... You said, it writes about 800Kb to the file before throwing up error ... That means file has been successfully opened. Now unless you have it embedded in a loop and are opening this file again and again, there is no reason why fopen should show an error ...
Either you have a misplaced loop or you have a misplaced suspicion :-)
Either you have a misplaced loop or you have a misplaced suspicion :-)
ASKER
well the situation is the following:
I have plenty of files like
a.c
a.h
b.c
b.h
d.cpp
d.for
.
.
.
e.t.c
So the fopen function is not in a loop(for,while...) but in a function which is called many times by the main.c program.What I really don't understand is that even if it is in a loop what's with the message about invalid argument?When does the perror generates this kind of message?
I have plenty of files like
a.c
a.h
b.c
b.h
d.cpp
d.for
.
.
.
e.t.c
So the fopen function is not in a loop(for,while...) but in a function which is called many times by the main.c program.What I really don't understand is that even if it is in a loop what's with the message about invalid argument?When does the perror generates this kind of message?
ASKER CERTIFIED SOLUTION
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Could you post some code?