sin(lon1-lon2)*cos(lat2)

/

sin(acos(sin(lat2)*sin(lat

)

distance = acos(sin(lat2)*sin(lat1)+c

Solved

Posted on 2005-04-10

Distance & Bearing between two waypoints?

Given a two Waypoints - for Example: N 44° 48.169 W 073° 25.625

N 44° 49.628 W 073° 26.610

How would you determine the bearing and distance between two waypoints?

Formula and answer to the waypoints given

thanks!

IElite

Given a two Waypoints - for Example: N 44° 48.169 W 073° 25.625

N 44° 49.628 W 073° 26.610

How would you determine the bearing and distance between two waypoints?

Formula and answer to the waypoints given

thanks!

IElite

12 Comments

sin(lon1-lon2)*cos(lat2)

/

sin(acos(sin(lat2)*sin(lat

)

distance = acos(sin(lat2)*sin(lat1)+c

http://www.circuitcellar.c

Earths radius:

3950 miles (6356.9 kilometres). Polar

3963 miles (6378.5 kilometres). Equitorial

Im not getting it! I do i convert these numbers so I can do an operation (Example: lon1-lon2)

073° 25.625

- 073° 26.610

I need to be able to do this from with in programming source code.....

IELite

http://www.google.com/sear

http://pollux.nss.nima.mil

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