asked on

How to separate values in getParamaters

Hello,

I have a form and a drop down list...
<form action="Servlet">
<select size="1" name="family">
out.print("<option>"+rs.getString(1)+"--"+rs.getString(2)+"</option>");
</select>
</form>

Now my Servlet accepts all form values.....
But since drop down values contains 2 values ie "rs.getString(1)" and "rs.getString(2)"
How should I separate this 2 values in my serlvet and assign to a string.

My Servlet:
.....
String soft = request.getParameter("family");
String s, p;
s = ??? HOW TO GET VALUES OF rs.getString(1); HERE ????
p =??? HOW TO GET VALUES OF rs.getString(2); HERE ????

<... making DB connection and calling Stored Procedure...>
cs0.setString(1,s);
cs0.setString(2,p);

rEGARDS

koppcha

you can get it as one whole string and split it.
>But since drop down values contains 2 values
What does this mean? you can select multiple values from the drop down box ? or dropdown box has one selection "--" seperated?

princehyderabad

ASKER

I mean how to split this whole string which I'm getting in form

koppcha

String soft = request.getParameter("family");
String[] s = soft.split("--");//hoping you string is like this "price--hyderabad";
s = s[0]
p =s[1]

princehyderabad

ASKER

Actually like this:

<option>"+ procResult.getString(1) +"  ("+ procResult.getString(2) +")</option>

Prince (Hyderabad)

1st word followed by two spaces "  " followed by "(" and 2nd word followed by ")"

koppcha

String soft = request.getParameter("family");
String[] s = soft.split("\\W+");//hoping you string is like this "price ("hyderabad")";
s = s[0]
p =s[1]

princehyderabad

ASKER

I already treid it but not working.
Your above code worked but that is not values really look like.

Let me give you the sample values I may get from DB.
===========
Family Versions
===========
BIG B Version 1.0
BIG IP Version 2.0
--------------------------

And I'm display it in HTML this way.
BIG B (Version 1.0)
BIG IP (Version 2.0)

Something like this, where "BIG B" is 1st string, and "Version 1.0" is 2nd string.

Please suggest me the suitable way.

koppcha

There will certainly be a better way than this .I wil let you know if i come across.Check if this work till that time.

Hoping Strin is of the form BIG B ("Version 1.0")
String[] p = s.split("\\(\\"");
System.out.println(p[0]);
String[] q = p[1].split("\\"\\)");
System.out.println(q[0]);

princehyderabad

ASKER

Errors on this line:
String[] q = p[1].split("\\"\\)");

I treid differ "" to remove ....
Error: excepted ; or )

Kuldeepchaturvedi

if you will always have "(" before the second value starts that this shd work..

String[] p = s.split("(");
System.out.println(p[0]);
System.our.println(p[1].subString(0,p[1].length()-1);

koppcha

Ok try this
Hoping Strin is of the form BIG B ("Version 1.0")
String[] p = s.split("\\(\"");
System.out.println(p[0]);
String[] q = p[1].split("\"\\)");
System.out.println(q[0]);

Manish

StringTokenizer stok = new StringTokenizer(soft , "--");
String first=sTok.nextToken();
String second=sTok.nextToken();

princehyderabad

ASKER

Didnt worked for both Kuldeepchaturvedi and koppcha last posting.

karanw my seperator is not "--" its something like this "BIG B (Version 1.0)"

Thought I'm runing my code temporary using "--" as seperator but I need to know the above solution.

Kuldeepchaturvedi

what is the output you are getting from my solution??

princehyderabad

ASKER

If this is the value BIG B (Version 1.0)

I'm getting same value BIG B (Version 1.0)

koppcha

You said your output is something like this right BIG B ("Version 1.0")
Isn't it?
If this is the case BIG B (Version 1.0)
then try
String[] p = s.split("\\(");
System.out.println(p[0]);
String[] q = p[1].split("\\)");
System.out.println(q[0]);

ASKER CERTIFIED SOLUTION

koppcha

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princehyderabad

ASKER

I agree your example is working no doubt.

But here is my value settings:
out.print("<option>"+procResult.getString(1)+"  ("+procResult.getString(2)+")</option>");

BIG B(space)(space)(Bracket)Version 1.0(Bracket)
or
BIG B  (Version 1.0)

Where BIG B is one value and Version 1.0 is other value.

koppcha

>BIG B(space)(space)(Bracket)Version 1.0(Bracket)
My earlier example works for this pattern ...Please post the output you are getting

princehyderabad

ASKER

my mistake.... sorry !! IT WORKED ..

Thanks ;o)