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Problem with Regular Expression

Hi,
I didn't know where to ask about this, but here seemed a popular place for Regular Expressions!

I am using NetTracker in order to sort the ip addresses of my visitors into Hosts. To do this, I need to use regular expressions.

I need to get all addresses (fictional addresses used here) from 200.100.129.1 to 200.100.129.127 in one host group and 200.100.129.128 to 200.100.129.255 in another host group. I have the following regular expression for the first host group:

200.100.129.(\d|[123456789]\d|11[0123456789]|12[01234567])

Unfortunately, this picks up for both host groups - 200.100.129.1 upto 200.100.129.255. Where am I going wrong?

Thanks.

manav_mathur

for group2

/200\.100\.129\.(1(?=(2(?=[8-9])|[3-9](?=\d)))|2(?=[0-5]))\d/

manav_mathur

Here's a sample that I got

use strict ;
use warnings ;
while(<DATA>) {
print if /200\.100\.129\.(1(?=(2(?=[8-9])|[3-9](?=\d)))|2(?=[0-5]))\d/ ;
}
__DATA__
200.100.129.255
200.100.129.126
200.100.129.127
200.100.129.128
200.100.129.129
200.100.129.130
200.100.129.131
200.100.129.12
200.100.129.174
200.100.129.110

output
200.100.129.255
200.100.129.128
200.100.129.129
200.100.129.130
200.100.129.131
200.100.129.174

geotiger

for group1

/200\.100\.129\.(1|1[0-9]|1[0-9][0-7])/

ozo

You are not anchoring your regular expression

/^200\.100\.129.(\d|[123456789]\d|11[0123456789]|12[01234567])$/
or
/^200\.100\.129.(\d|[1-9]\d|11[0-9]|12[0-7])$/

ozo

Sorry, make that
/^200\.100\.129\.(\d|[1-9]\d|1[01]\d|12[0-7])$/

ozo

Actually, that also matches 200.100.129.0 whereas you said 200.100.129.1 to 200.100.129.127
do you want that fixed too?
The problem with /200.100.129.(\d|[123456789]\d|11[0123456789]|12[01234567])/
was that it matches e.g. 200.100.129.2, and 200.100.129.2 can be found in 200.100.129.255

Electrotec

ASKER

ozo - thats a good point.

Revised request:

I require:
Group 1: 200.100.129.001 to 200.100.129.127
Group 2: 200.100.129.128 to 200.100.129.255

Thanks

ASKER CERTIFIED SOLUTION

ozo

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