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using parse_url is returning only the first arg=value for $a['query'].  How do we get all elements?

Posted on 2005-05-10
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Last Modified: 2008-03-17
Hi,
We are using parse_url to decode a url into its components.

The function is working correctly except that it is returning only the first url variable.
For instance if we do:
$a=parse_url("
http://www.futureshop.ca/catalog/proddetail.asp?pro=w&langid=EN&dept=3&sku_id=0665000FS10048110&catid=11130&newdeptid=15
")

$a['query'] returns only up to "pro=w".  We need it to return all elements of the request.  How do we do this?

Thanks.
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Question by:mcm-mgm
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Diablo84 earned 1000 total points
ID: 13973471
hmm, don't know why you are seeing that output,

<?php
$a = parse_url('http://www.futureshop.ca/catalog/proddetail.asp?pro=w&langid=EN&dept=3&sku_id=0665000FS10048110&catid=11130&newdeptid=15');

echo '<pre>';
print_r($a);
echo '</pre>';
?>

outputs:

Array
(
    [scheme] => http
    [host] => www.futureshop.ca
    [path] => /catalog/proddetail.asp
    [query] => pro=w&langid=EN&dept=3&sku_id=0665000FS10048110&catid=11130&newdeptid=15
)

Which is correct.

Failing that you can get the current query string contents using: $_SERVER['QUERY_STRING']

or, if you need to get it from a string URL rather then the current one you could use:

$url = 'http://www.futureshop.ca/catalog/proddetail.asp?pro=w&langid=EN&dept=3&sku_id=0665000FS10048110&catid=11130&newdeptid=15';
echo substr($url,strpos($url,'?')+1);

Diablo84
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