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Repair Network Connection Using C#

Good afternoon,

Normally, when our Wireless network cuts out, I right click on the wireless icon in the system tray and select "Repair". Is there a way to accomplish this using C#? Thanks!

Yurich

there is, but you'll have to start your c# application and click repair on it, then it will move your mouse cursor to your systray, right-click the icon , and select "repair"...

if you want to automate it, you'll have to create a resident-program that would check the state of connection all the time and if it's not connected - see above.

regards,
yurich

fattumsdad

ASKER

Yurich,

How do I have the mouse cursor move to the systray? That sounds interesting!

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Yurich

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fattumsdad

ASKER

That works great, and I now have the cursor jumping directly to the network icon... however, I can't figure out how to simulate the right-click and then left-clicking "repair".

Yurich

well, that one will be a bit more complicated...
you'll have to use api function since i don't know other ways of doing it.

using System.Runtime.InteropServices;

...

// somewhere in your class scope (namespace)
[ DllImport( "user32.dll" )]
private static extern void mouse_event( UInt32 dwFlags, UInt32 dx, UInt32 dy, UInt32 dwData, IntPtr dwExtraInfo );

private const UInt32 MOUSEEVENTF_LEFTDOWN = 0x0002;
private const UInt32 MOUSEEVENTF_LEFTUP = 0x0004;
private const UInt32 MOUSEEVENTF_RIGHTDOWN = 0x0008;
private const UInt32 MOUSEEVENTF_RIGHTUP = 0x0010;

private void SendLeftClick()
{
      mouse_event( MOUSEEVENTF_LEFTDOWN, 0, 0, 0, new System.IntPtr());
      mouse_event( MOUSEEVENTF_LEFTUP, 0, 0, 0, new System.IntPtr());
}

private void SendRightClick()
{
      mouse_event( MOUSEEVENTF_RIGHTDOWN, 0, 0, 0, new System.IntPtr());
      mouse_event( MOUSEEVENTF_RIGHTUP, 0, 0, 0, new System.IntPtr());
}

// then, somewhere in the same function where you moved your button to the icon on the systray:
...
SendRightClick();
// pick the right values for ?? to move your cursor just slight above your appeared menu
Cursor.Position = new Point( Cursor.Position.X - ??, Cursor.Position.Y - ?? );
SendLeftClick();
...

well, that should be pretty much it,
good luck,
yurich