if-else with mod and CSS

What error are u getting ?

 if($i%2): $color = "#FFFFFF"; else: $color = "#CCCCCC"; endif;

is assume this is related to the alternate table row color ?
then use this
$s = "<table>\r\n";
for($x=0;$x<count($array);$x++){
    if($x/2 == round($x/2)){
        $c = "class=\"normal\"";
    }else{
        $c = "class=\"other\"";
    }
    $s .= "<tr>";
    $s .= "<td $c>".$array[$x]."</td>";
    $s .= "</tr>\r\n";
}
$s .= "</table>\r\n";
echo $s;
$s .= "</table>\r\n";
echo $s;
or
or Heres a simple ex:http://www.phpfreaks.com/tutorials/5/0.php

//try this
<?php
echo "<table border=0 cellspacing=0 cellpadding=0>";
$num=20;
for($i=0;$i<$num;$i++){

  if($i % 2 ==0)
  {
    $bgcolor='#f3f3f3';
  }
  else
  {
    $bgcolor='#e3e3e3';
  }

  // echo the table content with $bgcolor
  echo "<tr bgcolor=$bgcolor><td> This is line number $i </td></tr>";

// close loop
}

// close table
echo "</table>";
?>

That's almost what I have:

for ($i=0; $i<count($name); $i++)
{
  echo if ($i % 2==1)
  {
     echo '<tr class=\"other\">';
  }
  else
  {  
     echo '<tr class=\"normal\">';
  }
...echo stuff
}

echo if should be if. Nothing happens, no error.

why an echo for the if stmnt ??
"echo if ($i % 2==1)" shouldnt that be if ($i % 2==1)
try this

if ($i % 2==1)
{
    $myclass='other';
  }
  else
  {
    $myclass='normal';
  }
echo "<tr class=$myclass><td> .....";

 

Not getting it, here's all related code:

tr.normal
{
   background-color:#FFFFFF;
}

tr.other
{
background-color:#000000;
}
...
for ($i=0; $i<count($name); $i++)
{
if ($i % 2==1)
{
$myclass='other';
}
else
{
$myclass='normal';
}
echo "<tr class=$myclass>";

echo ...
}

Change
if ($i % 2==1)
to
if ($i % 2==0)

Nope. I think I'm overlooking something.

Check the ex at :http://www.phpfreaks.com/tutorials/5/0.php
Are u getting any output ordoes teh screen show blank>

IE gives me all green, firefox gives me nothing.

finally got it sajuks. I copied and pasted exactly from that .php file you sent me.

Thank you for your help

Bob