help with a string

If fullName.IndexOf("[")>0 then
    fullName = fullName.Substring(fullname.indexof("["))
end if

It should work this way as well

Dim fullName() As String

fullName = result.Properties("displayName")(0).Split("["c)

Cast from type 'String()' to type 'String' is not valid.


on all of them

nevermind...i see what i did

is there a way to split everything after a space and then [

if the string was LastName, FirstName [whatever]
then i would want my value to be
LastName, FirstName

i tried
fullName = result.Properties("displayName")(0).Split(" ", "["c)
but it returns
LastName,

fullName = result.Properties("displayName")(0).Split(" [")

tried that and got...
Character constant must contain exactly one character.

Alright then... I'll stand by my original suggestion:

 If fullName.IndexOf("[")>0 then
    fullName = fullName.Substring(fullname.indexof(" ["))
end if

oops

If fullName.IndexOf(" [")>0 then
    fullName = fullName.Substring(fullname.indexof(" ["))
end if

wouldn't that return everything to the right of the [

[whatever]
instead of
LastName, FirstName

??

sorry... forgot it was start,length... not just length...

If fullName.IndexOf(" [")>0 then
    fullName = fullName.Substring(0,fullname.indexof(" ["))
end if

https://www.experts-exchange.com/questions/21482222/How.html

Sorry I was away from my desk.

        Dim SplitName() As String

        SplitName = fullName.Split(" "c)

Sorry I was away from my desk.

Imports System.Text.RegularExpressions

        Dim SplitName() As String

        SplitName = fullName.Split(" "c)
        SplitName(0) has the first part of the name just before the space
        SplitName(1) Has everything after the space

I am using Regular Expressions to remove the { } if any

        Dim m As Match = Regex.Match(SplitName(1), "\[(?<LName>.*)\]|(?<LName>.*)")
        SplitName(1) = m.Groups("LName").Value

Sorry about the delay, fires to put out
       

Thanks guys...it's all working great now! :-)