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Java: Get part before and after decimal point

How to get the 2 parts from a double value: 3.141592654 ???

part1 = 3
part2 = 141592654

conver the dobule to String and then do a indexOf ..

something like..

Double d = new Double(3.1415......);
String sd = d.toString();
int idx = sd.indexOf(".");
String part1 = sd.substring(0,idx);
String part2 = sd.subString(idx);

StillUnAware

Double d = new Double(3.141592654);
long part1 = d.longValue();
long part2 = d.toString().substring(d.toString().indexOf('.'), d.toString().length());

zzynx

What are part1 & part2?
String's, doubl's, long's??

ASKER CERTIFIED SOLUTION

dberner9

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dberner9

for strings:
String[] parts = new Double(d).toString().split("\\.");
String part1 = parts[0];
String part2 = parts[1];

for longs:
String[] parts = new Double(d).toString().split("\\.");
Long part1 = Long.parseLong(parts[0]);
Long part2 = Long.parseLong(parts[1]);

SOLUTION

zzynx

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Kuldeepchaturvedi

dberner9's code will work for JDK1.4 & above but its if you are using 1.4 then its the right way of doing it

go4java

ASKER

will test on monday and come back to you. thanks so far :-)

emad_sarhan

>>double d = 3.141592654;
>>long integerPart = (long)d;
>>double decimalPart = d - (double)integerPart;

intelligence solution, but
part2 (decimalPart) will contains ( . ) /*dot*/ at the front ..

Mayank S

>> part2 (decimalPart) will contains ( . ) /*dot*/ at the front ..

That is what is required? I guess you can also use:

long integerPart = ( long ) d ;
double decimalPart = d - integerPart ; // no need to type-cast

zzynx

thanks