debugging scheduled task

I have a task scheduler that runs:
C:\php\php.exe -r C:\www\test.php

test.php:
<?php
  $file = "C:\\php\\test.txt";
  $fp = fopen($file, "w+");
  $datetime = date("r");

  fwrite($fp, "this is a test.\r\n");

  for($i = 0; $i < 10; $i++)
  {
    $j = $i * $i;
    fwrite($fp, "$i squared is $j.\r\n");
  }

  fwrite($fp, "the time is: $datetime\r\n");
  fwrite($fp, "test complete.");
 
  fclose($fp);
?>

When the time hits, I see the command prompt flash...but the file does not get written. Is there anyway to see the output? I'm not seeing anything in event viewer.
LVL 6
jstretchAsked:
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JB04Commented:
you should be using the -f flag instead of the -r flag, the -r flag runs some code you enter, the -f flag runs the given file, so change it to the following and it should work:-

C:\php\php.exe -f C:\www\test.php

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jstretchAuthor Commented:
Sorry for the delay, been on the road.

Tried the -f flag, still the same results..nothing. No way of seeing the code or any errors?
jstretchAuthor Commented:
I tried:

"C:\Program Files\Internet Explorer\IEXPLORE.EXE" "http:\\localhost:8080\test.php"

and it worked, but opened a browser window, which I dont want because it will eat up memory. Is this a permission issue?
jstretchAuthor Commented:
Was a permission issue, the -f also helped. Thanks
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