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Help with **

int *Function(int **,int *,int); //prototype

int *Function(int **y,int *z,int r)//function

Hi, can someone explain exactly what this is, and when it would be used?
Or possibly provide a tutorial on this subject?

ASKER CERTIFIED SOLUTION

jhshukla

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amit_g

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grg99

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List244

ASKER

What would I be doing wrong here?

#include <iostream>

using namespace std;

int MyFunc(int **Array);

int main()
{
      int ret = 0;
      int x[3][3]= {{1,2,3},{4,5,6},{7,8,9}};
      ret = MyFunc(x);
      return 0;
}

int MyFunc(int **Array)
{
      return 0;
}

SOLUTION

thekng

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amit_g

int x[3][3] has dimension information in it i.e. it is int *x[3]. While **Array doesn't have any dimention information in it. So the are different datatypes and so can't be assigned to each other. Only one dimension can be "not specified". So you need to change it to

#include <iostream>

using namespace std;

int MyFunc(int (*Array)[3]);

int main()
{
int ret = 0;
int x[3][3]= {{1,2,3},{4,5,6},{7,8,9}};
ret = MyFunc(x);
return 0;
}

int MyFunc(int (*Array)[3])
{
return 0;
}

OR

#include <iostream>

using namespace std;

int MyFunc(int Array[][3]);

int main()
{
int ret = 0;
int x[3][3]= {{1,2,3},{4,5,6},{7,8,9}};
ret = MyFunc(x);
return 0;
}

int MyFunc(int Array[][3])
{
return 0;
}

SOLUTION

MadDavid

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