a question about unix programming

dear:

in linux c programming
how to change int to char
and how to delete the content of a file(but don't delete the file)?

Thank you!
wolf415Asked:
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liviutudorCommented:
Do you mean you want to convert the int value 9 into character '9'?
Simply do char c = '0' + int_value -- assuming that you have already tested that int_value is positive and not bigger than 9.
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liviutudorCommented:
P.S. If you want to basically truncate the file to 0 bytes -- which is what i understand you are trying to achieve -- simply call fopen() with a parameter of "w" -- according to the man pages, fopen called with this parameter "Opens an empty file for writing. If the given file exists, its contents are destroyed." -- so after calling FILE * fp = fopen( "filename", "w" ); and then fclose(fp); you will end up with a file of 0 bytes -- either whether it existed or not before.

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NopiusCommented:
1) If the question is 'how to get character for given digit from '0' to '9', then I aggree with livitudor.
If the question is "how to cast from int to char", there is no easy way to change int to char due to non-portability between different CPU types and compilers.
2) I aggree with liviutudor, fopen() is ok, also you may also call (this is a direct syscall without extra payload):
close(open("filename", O_WRONLY | O_TRUNC, 0766));
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ozoCommented:
#include <unistd.h>
truncate("filename", 0);

#include <stdio.h>
char string[100];
int i=9;
sprintf(string,"%d",i);
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wolf415Author Commented:
ThANK YOU!
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