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shell script - check for entering date in the correct format on the command line

Posted on 2006-03-22
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Last Modified: 2013-12-26
I'm writing a script that needs to have the date passed as a argument on the commnad line.  The date must be entered in the correct format, which in this case is, MM-DD-YYYY.  This also need to check to see if they even entered the date on the command line.

Does anyone have a snippet of code that will perform that check?

Thanks,

Lisa
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Question by:lphillips120898
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ahoffmann earned 500 total points
ID: 16258024
assuming programming in sh, use something like:

echo "$1" | awk -F- '($1!~/[0-1][0-9]/){print "bad month";exit(1)}($2!~/[0-3][0-9]/){print "bad day";exit(1)}($3!~/[1-9][0-9][0-9][0-9]/){print "bad year";exit(1)}'
[ $? -ne 0 ] && exit 1

# regex in awk to be improved in many ways ;-)
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Author Comment

by:lphillips120898
ID: 16259182
Thanks, worked like a charm!
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Author Comment

by:lphillips120898
ID: 16259331
question - I put the code on separate lines to make it easier to read, breaking at the ";"  Would you explain how the scripts works?  If it's too much trouble for the amount of points I understand.

thanks,

Lisa

echo "$MDATE" | awk -F- '($1!~/[0-1][0-9]/){print "bad month"
exit(1)}($2!~/[0-3][0-9]/){print "bad day"
exit(1)}($3!~/[1-9][0-9][0-9][0-9]/){print "bad year"
exit(1)}'
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LVL 51

Expert Comment

by:ahoffmann
ID: 16260721
awk splits each line (only one should reach) at the - into words (-F- option), then checks the words ($1, $2, $3) using a simple regex. If the regex does not macth it prints the message and exits awk with an status code 1.
My sample uses awk's status code to exit the script too:  [ $? -ne 0 ]
Take care that the suggested regex are lazy, it allows 19 as month ...

> .. put the code on separate lines ..
take care that this depends on your version of the shell, a human reader friendly version might be:

echo "$MDATE" | awk -F- '
  ($1!~/[0-1][0-9]/){ print "bad month"; exit(1) }
  ($2!~/[0-3][0-9]/){ print "bad day"; exit(1) }
  ($3!~/[1-9][0-9][0-9][0-9]/){ print "bad year"; exit(1) }
'

but I prefer onliners ;-)
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Author Comment

by:lphillips120898
ID: 16268429
Thank You!  It is easier for me to understand now - and I prefer multiliners  8^)
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Expert Comment

by:CuthbertDibbleGrub
ID: 16755312
Our Solaris boxes have a ckdate shell command which does exactly what you're after, so could be incorporated into your script easily if available.  I mention this as the accepted answer above will not throw out 02/33/2006, 19/19/1999, 02/31/2006 etc.  ckdate will detect leap years as well.
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