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# Conditional Statements Structure Question

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Hello Experts,

I'm trying to help my daughter with her C homeowork.  I'm a longtime developer but have not worked in C in decades.  She has the following problem:

The mathematical operation min(x,y) can be represented by the conditional
expression

(x < y) ? x : y

In similar fashion, using only conditional expressions, describe the
mathematical operations:

min(x, y, z)             and          max(x,y,z,w)

I understand how the min(x,y) translate into (x < y) ? x : y
and that (x < y) ? x : y  is tha same as If x < y then x else y
but am drawing a blank as to how to code the two problems.

Can anyone help?

Thanks,
Steve
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Commented:
min(x,y,z)
(x<y) ? ((x < z) ? x : z) : ((y < z) ? y : z) ;

i hope this works....
the same way you can write to max(x,y,z,w)

CERTIFIED EXPERT
Commented:
hi Waterstone,

as you wrote:

min2(x,y)   (x < y) ? x : y;

so

min3(x,y,z)   min2( min2( x, y ), z );

and

max4( x, y, z, w )    max2( max2( max2( x, y ), z ), w );

hope it helps
ike

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CERTIFIED EXPERT
Top Expert 2006

Commented:
#include <stdio.h>

int main()
{
int i=10,j=3,k=12,l=9;
int max,min;

min = (i<j)?((i<k)?i:k):((j<k)?j:k);

max = (j>i)?((j>k)?(j>l?j:l):(k>l?k:l)):((i>k)?(i>l?i:l):(k>l?k:l));

printf("min %d max %d",min,max);
}

Cheers!
sunnycoder

Commented:
u can write the solution for finding minimam of N number,
first u hav to pass the numbers into the array
pass the array and the no. arg over the function named min
the function is like this,
int min(int arr,int noarg)  //arr  is the array which are having no.//noarg  is the no. arguments
{
int i,min=arr;
for(i=1;i<noarg;i++)
{
min=(min<arr[i])?min:arr[i]);
}
return min;
}

Commented:
Hi Waterstone,

They're probably looking for something like:

#define Min(x,y) ((x)<(y)?(x):(y))
#define Min3(x,y,z) (Min(x,y)<(z)?Min(x,y):(z))
...

Paul
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