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PHP, regex and lazy star

Posted on 2006-03-24
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Last Modified: 2012-08-13
Hello

I need to write a line of code in PHP to remove image tags from a string.

I am trying the following...

echo eregi_replace("<img .*?>", "", "some string <img src=> with images <img src=   >");

...but keep getting the "Warning: eregi_replace(): REG_BADRPT in .../test.php on line ..." errormessage.

If I remove "?" from the regex it doesn't throw an error, but doesn't work as needed either doing a greedy match.

Please help

Thank you
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Question by:AdmiralHorror
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Tomeeboy earned 200 total points
ID: 16282775
Try this for removing image tags:

$string = preg_replace('/<img (.*?)src=(.*?)>/i', "", $string);
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by:AdmiralHorror
ID: 16283325
Ok, that worked, thank you very much.

However, could you please explain to me the meaning of "/" in front of the "<" and the meaning of "/i"
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by:Tomeeboy
ID: 16283522
I think that the front slashes just define where the actual pattern starts/stops... though I'm not 100% sure on that :)  I always put them around a regex pattern for any PHP functions that use a regex pattern.  The "i" makes the pattern case insensitive.
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