asked on

solve this my sql exception in jsp

<%@ page language = "java" import ="java.sql.*" %>
<html>
<body>
<%

Connection con = null;

try
{
Class.forName("com.mysql.jdbc.Driver");
con = DriverManager.getConnection("jdbc:mysql://localhost:3306/javatest");

Statement st = con.createStatement();
ResultSet rs = st.executeQuery("select * from counter");
%>
<table border =2>

<%
while(rs.next())
{
%>
<tr>
<td><%= rs.getString(1)%></td>

<td><%= rs.getString(2)%></td>

<td><%= rs.getString(3)%></td>

</tr>

<%
}
%>
</table>
<%
}
catch(Exception d)
{
out.println("can not display the records");

}

finally
{
if(con != null)
{
try
{
con.close();
}
catch(SQLException e)
{
out.println("Error closing the connection");
}
}
}
%>
</body>
</html>

i got exception for this code

ype Exception report

message

description The server encountered an internal error () that prevented it from fulfilling this request.

exception

org.apache.jasper.JasperException: org/aspectj/lang/Signature
      org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:510)
      org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:375)
      org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:314)
      org.apache.jasper.servlet.JspServlet.service(JspServlet.java:264)
      javax.servlet.http.HttpServlet.service(HttpServlet.java:802)

root cause

javax.servlet.ServletException: org/aspectj/lang/Signature
      org.apache.jasper.runtime.PageContextImpl.doHandlePageException(PageContextImpl.java:858)
      org.apache.jasper.runtime.PageContextImpl.handlePageException(PageContextImpl.java:791)
      org.apache.jsp.simplejdbc_jsp._jspService(org.apache.jsp.simplejdbc_jsp:119)
      org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:97)
      javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
      org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:332)
      org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:314)
      org.apache.jasper.servlet.JspServlet.service(JspServlet.java:264)
      javax.servlet.http.HttpServlet.service(HttpServlet.java:802)

root cause

java.lang.NoClassDefFoundError: org/aspectj/lang/Signature
      java.lang.Class.forName0(Native Method)
      java.lang.Class.forName(Unknown Source)
      org.apache.jsp.simplejdbc_jsp._jspService(org.apache.jsp.simplejdbc_jsp:52)
      org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:97)
      javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
      org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:332)
      org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:314)
      org.apache.jasper.servlet.JspServlet.service(JspServlet.java:264)
      javax.servlet.http.HttpServlet.service(HttpServlet.java:802)

note The full stack trace of the root cause is available in the Apache Tomcat/5.5.15 logs.

i put mysql- jav connector 5.0.0b.jar into C:\Program Files\Apache Software Foundation\Tomcat 5.5\webapps\ROOT\WEB-INF\lib this directory

could i want to set ant classpath?

radarsh

Alright stmani,

Remove the mysql-connector-java-XXXX-bin-g.jar from your classpath
and just add the mysql-connector-java-XXXX-bin.jar

the -g jar is a debug version and should not be in your classpath

________
radarsh

Manikandan Thiagarajan

ASKER

now it dispalys

can not display records.

how could i know counter table structure in javatest database in mysql

radarsh

Open mysql command line and type

desc counter;

________
radarsh

ASKER CERTIFIED SOLUTION

radarsh

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See answer

Manikandan Thiagarajan

ASKER

if i run through eclipse that shows page can not be displayed.

it would be run with out ecclipse.

i create a dynamic webproject is called jdbcjsp.

right click that one add jsp file to that.

when i right clikc jdbcjsp folder and select option run as server.

it shows page can not be displayed.

could i modify workspace in ecllpse.

http://localhost:8090/JDBCJSP THIS URL SHOWS IN ECCLIPSE.

FILE NAME IS JDBC.JSP.

IS IT CORRECT.

HOW COULD I RUN THIS PROGRAM IN ECCLIPSE.

radarsh

Where did you put your jsp? It should be directly under WebContent folder.
Make sure your server is running.

Hit http://localhost:8090 and see if you get something.

How is it 8090? Did you change the port? By default it will be 8080.

________
radarsh

Manikandan Thiagarajan

ASKER

jsp file is there in webcontentfolder only

>>Hit http://localhost:8090 and see if you get something.

it shows page can not be displayed

>>How is it 8090? Did you change the port? By default it will be 8080.

already i changed the port

radarsh

That means your server is not started! Make sure you start the server
properly and then try rest of the things.

________
radarsh

Manikandan Thiagarajan

ASKER

how to start the server.

radarsh

stmani, all this is not relevant to your original question. All you asked was
how to get rid of that exception. And I guess that's solved.

You need to read the tomcat guides for information on how to do things.
http://tomcat.apache.org/tomcat-5.5-doc/index.html

________
radarsh

Manikandan Thiagarajan

ASKER

now i got this exception

i put

%>
</table>
<%
}
catch(Exception d)
{
out.println(d.printStackTrace());

}
that would causes an exception like this
An error occurred at line: 35 in the jsp file: /simplejdbc.jsp

Generated servlet error:
The method println() in the type PrintStream is not applicable for the arguments (void)

      org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:510)
      org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:375)
      org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:314)
      org.apache.jasper.servlet.JspServlet.service(JspServlet.java:264)
      javax.servlet.http.HttpServlet.service(HttpServlet.java:802)

root cause

radarsh

>> out.println(d.printStackTrace());

Should be either out.println(d.getMessage());

or d.printStackTrace();

________
radarsh

Manikandan Thiagarajan

ASKER

Access denied for user ''@'localhost' (using password: NO)

now that would give message like this