Byte information

Dear Sirs,

I have read a single byte from a serial port and the value is &H89

This byte contains two bits of information (the first four bits contain the first part the last four bits contain the other value)  How can I seperate these two pieces of data from this single byte?

Many thanks
watersidedesignsAsked:
Who is Participating?
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

ElrondCTCommented:
If the byte is stored in a string variable:

dim strInput as String
dim intInput as Integer
dim intHigh as Integer
dim intLow as Integer
' load strInput here
intInput = Asc(txtIn.Text)
intHigh = intInput \ 16        ' Upper 4 bits
intLow = intInput And 15    ' Lower 4 bits

Note the use of \ rather than / for division; you want integer division, dropping the remainder.
0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
ElrondCTCommented:
Grr, replace txtIn.Text with strInput. I was copying from my test code and forgot to adjust that. Sorry!
0
watersidedesignsAuthor Commented:
Hi ElrondCT,

Thats most helpful - thanks.
0
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
Visual Basic.NET

From novice to tech pro — start learning today.

Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.