Awk (or Sed) to show current field number from the Field Seperator

How can I awk (or sed) something to do a search and print out the Field NUMBER (position in the line) when it finds a match?

Example File has 3 lines:

This is - a test file.
This is a - test file.
This is a test - file.

Find the positions of the "-"

Desired Outcome:

I can grep, awk -F-, and sed to find them (and / or do other things), but thought awk would have had a variable like FS or something that might help out.

Thank you,
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try grep -n

-n prints line number in file
sorry my mistake, just reread your example, ignore what I wrote
have a look at using index in AWK, I think that might be it
hopefully some other expert can help ya cos Im now off home
have a good evening, sorry about my cockup
awk '{for(n=1;n<=NF;n++){if($n=="-")print n}}' file

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genehackmanAuthor Commented:
That worked perfectly !
Thank you,
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