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A simple polygon has a non-intersecting boundary, while a complex polygon has an intersection somewhere. So a natural approach would be to check whether any two sides of the polygon intersect each other.<br />
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The intersection of 2 lines can be tested with an algorithm like this:<br />
<a href="http://www.macs.hw.ac.uk/~alison/ds98/node114.html" rel="ugc">http://www.macs.hw.ac.uk/~alison/ds98/node114.html</a><br />

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A simple polygon has a non-intersecting boundary, while a complex polygon has an intersection somewhere. So a natural approach would be to check whether any two sides of the polygon intersect each other.

The intersection of 2 lines can be tested with an algorithm like this:
http://www.macs.hw.ac.uk/~alison/ds98/node114.html [http://www.macs.hw.ac.uk/~alison/ds98/node114.html]


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I've tried doing an edge-edge test, but it fails for some reason. Could it be that an edge sharing the same node brings back true when doing the edge on edge test?
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I've tried doing an edge-edge test, but it fails for some reason. Could it be that an edge sharing the same node brings back true when doing the edge on edge test?

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Yes, this sounds plausible. But you can simply omit to test the neighbor edges as they will never intersect each other.
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Yes, this sounds plausible. But you can simply omit to test the neighbor edges as they will never intersect each other.

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I have two arrays, storing the x and y values of the polygon. <br />
<br />
I want to find out whether the polygon is simple or complex.<br />
<br />
The polygon can be concave and is 2d.<br />
<br />
Can someone possibly provide suggestions.<br />
<br />
Many Thanks.
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I have two arrays, storing the x and y values of the polygon. 

I want to find out whether the polygon is simple or complex.

The polygon can be concave and is 2d.

Can someone possibly provide suggestions.

Many Thanks.

Determine whether a polygon is complex or simple

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