Int to Binary Conversion

Is there also a way to just use printf to display an int as a binary number?

This is a very common homework question. May we know why you need this routine?

Also ...
>I've searched on here for some of the examples, however didn't find any I really liked..
What is that you are exactly looking for? Why was the existing code not good enough?

Cheers!
sunnycoder

Well actually it isn't that I didn't like it.. I tried using some of the examples.. and they just gave me seg faults.. can't really figure out why either.

An int actually is a binary number already.

You can print it in hexadecimal with:
printf( "%x", intval );
or formatted in C-style and with all 4 bytes present:
printf( "0x%.8x", intval );

to print it to a string use:
char str[ 20 ];
sprintf( str, "0x%.8x", intval );

to get a char* of the 4 bytes of an int you can simply cast the pointer to it
char * barr =  (char *) &intval;
and access the bytes this way:
char firstByte = barr[ 0 ];
but the ordering of the bytes is processor dependant if you do it this way (little/big endian)

to do this processor independant you can use:
char barr[ 4 ];
barr[ 0 ] = (char) ( intval >> 24 );
barr[ 1 ] = (char) ( intval >> 16 );
barr[ 2 ] = (char) ( intval >>  8 );
barr[ 3 ] = (char) intval;

I'm not sure if this is what you meant.

I apologize.