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Hi All

I need a formula to calculate the area of a trinagle, but theres a twist. The triangle as a curved face. Heres a picture of what I am talking about

http://www.clothier.org.uk/picture1.jpg

I need to calculate the area using only the dimmensions specified on the drawing, A, B & C.

Many Thanks

I need a formula to calculate the area of a trinagle, but theres a twist. The triangle as a curved face. Heres a picture of what I am talking about

http://www.clothier.org.uk/picture1.jpg

I need to calculate the area using only the dimmensions specified on the drawing, A, B & C.

Many Thanks

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L=sqrt(A²-(C/2)²)

R=(4(B-L)²+C²)/(8*(B-L))

A=R²arcsin(C/(2R))+C(L-sqr

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Start your 7-day free trialArea = 0.5*a^2*(2*(sin^-1(a/(0.5*

Also, I assumed the angles created by the intersection of lines b & c to be 90 degrees.

the drawing is a sector of a circle. is is also 2 identical sectors of the same circle. I used one of the triangles created by these 2 identical sectors of the same circle to find the corresponding angle. This angle was doubled to find the angle of the original sector (hence, x = 2z).

It has been a while, but I think this is correct.

Oceanbeach, The angle is not always going to be 90 degrees and it also is not always going to be a sector of a circle. The formula that you have given is correct based on that so I have awarded you some points.

ozo, Yes you have answered this for me before but after I accepted I couldn't get the formula to work.

L=sqrt(D²-(W/2)²)

R=(4(Z-L)²+W²)/(8*(Z-L))

A = (R²sin¯¹(W/(2R))+W(L-sqrt(

I think that the problem was with this part sin¯¹

I note that this time you have changed it to arcsin

This may just be not knowing what I am talking about but this made it work.

Thanks again!

You know what they say about assumptions....

Aside from bad assumptions, I am glad my thought process was correct. I sure hope I at least helped since you gave me an assist.

Happy number crunching!

Math / Science

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Area of a circle = Pi*r^2.

Area of a secotor of a circle = 0.5*r^2*x

angle of sector = x = 2z

r = a = b

sin z = a/(0.5*c)

z = sin^-1(a/(0.5*c))

x = 2*(sin^-1(a/(0.5*c))) = angle of sector of circle

therefore:

Area of a secotor of a circle = 0.5*r^2*x

= 0.5*r^2*(2*(sin^-1(a/(0.5*