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How to use variables names in other variables ?

Posted on 2006-04-04
Medium Priority
Last Modified: 2008-03-04
I am trying to retrieve some fields from database within phpnuke (PHP / MySQL CMS)
the field in question is the user_regdate (The date the user registered on the site)
The format of the field is MMM DD, YYYY i.e. Jan 10, 2006

I wanted to pull the results from the database and populate a table with how many members joined that month

Code i have so far is:-

            echo "<table>";
            echo "<tr><td>Year</td><td>Month</td><td>Users</td></tr>";
            $querystring = "SELECT user_regdate FROM nuke_users";
            $query = $db->sql_query( "$querystring" );
            while (list($regdate) = $db->sql_fetchrow($query)) {
                  list($monthday,$year) = explode(",",$regdate);
                  list($month, $day) = explode(" ", $monthday);
                  $year = trim($year);
//                  echo "Month - $month<br>Year - $year<br><br>";
                  if ($month=="Jan" && $year=="2006") {
                        echo "match<br>";
      echo "Jan 2006 - " . ${Jan2006} . ":<br>";

This does pull the info out and split it into variables i.e. $day, $month and $year but i am then simply trying to get it to create matching set variables that accummulate up i.e. Jan2006, Feb2006, Mar2006 etc and then adding 1 to each variable if it matches to get total amount per month

The problem is that the adding up code "$month.$year++; doesnt seem to work, i have also tried $$month$year++;

I know i have used this before somehow but too long ago to remember and cant find the code snippet now !!
Question by:davidburley
LVL 49

Expert Comment

ID: 16371890
You can have
$date = $month.$year;


Author Comment

ID: 16372534
ah y but that doesnt populate my variables properly i.e. i want a seperate variable for every month of the year for every year
i.e. $Jan2005, $Feb2005, $Mar2005, $Apr2005 etc and each month would simply hold the count of how many users joined during that month.
LVL 17

Expert Comment

ID: 16372945
$arrayMonths = array('Jan2005' => 0, 'Feb2005' => 0, 'Mar2005' => 0, 'Apr2005 => 0,....)

Now when you say: $Jan2005 you could just do:

To Increment them:

That sound ok for you?
Joe P
LVL 17

Accepted Solution

BogoJoker earned 500 total points
ID: 16372984
I initailize the array with a single line syntax:
$array = array('a' => 0)

That is the same as:
$array = array();
$array['a'] = 0;

I am not familier with 2d arrays in php but I am sure experts like Roonaan know how.  They could potentially improve my code so that you have a seperate section for each month, like this:
$arrayMonths['Jan']['2005'] = 0;
Which would be different from $arrayMonths['Jan']['2006'];

But I don't know how to do that yet, It will probably not be too difficult if you are intrested in such an improvement.
Joe P

Note: You can also use this with the code I gave you:
$registerTime = 'Jan2005';
echo $arrayMonths[$registerTime]; // this will print out the current number in $arrayMonths['Jan2005'] so it is variable safe inside those []s

Assisted Solution

x95guzik earned 500 total points
ID: 16373314
Below is a simplified example with the method you are looking for I believe.

//put the 'm' in front for PHP will not accept a number for its variable first character
$month = "m12";
$year = "2005";

$monthYear = $month.$year;
${$monthYear} = 16;

$month = "m01";
$year = "2006";

$monthYear = $month.$year;
${$monthYear} = 12;

echo $m122005;
echo "<BR>".$m012006;


echo "<br>".$m012006;

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