Unix Korn Shell - Converting Strings to Dates

I am pulling the Day,  Month , Year from various files using 'ls -l' to allow me to compare files in one directory against another.  The month is coming out as 'Oct'.  The problem is I need to convert my final string e.g. '10/May/2005' to a date format to allow me to filter which has the latest date etc.  I have trawled various sites with no answers.

I have used awk to extract the positions from ls-l process.   Any help appreciated....
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You can use awk printf command to do that
echo '10/May/2005' | awk -F/ 'BEGIN{m["Jan"]=1;;m["Mar"]=3;m["Apr"]=4;m["May"]=5;m["Jun"]=6;m["Jul"]=7;m["Aug"]=8;m["Sep"]=9;m["Oct"]=10;m["Nov"]=11;m["Dec"]=12}{printf "%4d-%02d-%-2d",$3,m[$2],$1}'

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echo '10/May/2005' | awk -F/ 'BEGIN{m["Jan"]=1;;m["Mar"]=3;m["Apr"]=4;m["May"]=5;m["Jun"]=6;m["Jul"]=7;m["Aug"]=8;m["Sep"]=9;m["Oct"]=10;m["Nov"]=11;m["Dec"]=12}{printf "%4d-%02d-%02d",$3,m[$2],$1}'
You might step back and ask if you can get 'ls' to give what you want.  If you are using Linux, or GNU 'ls', you could try reformatting the output of 'ls' instead, as with:

    ls -l --time-style='+%Y/%m/%d-%M:%H:%S'

Which will give dates listed like this:    2006/03/17-10:06:03
btcodemanAuthor Commented:
Ozo,  thanks for the answer  - much appreciated.
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