Mathmatically if we assume daily both meet at the 0km point at 0:00.

We know the distance to the crossing is 5km and it will take the cyclist 30min to reach 0km (5km@10kmph). Since they normally meet at the crossing (not this point) and are travelling in parallel. We know the cyclist is (overall) 25min late. We must assume the train is NOT late and hence will be at the crossing at 0:00 (5km and 5min hence). The train must be moving at 1km/min or 60kmph.