Setting the ValueMember of a listbox in Windows Forms...

I have been doing everything in asp.net lately so I am struggling with this simple issue in a Windows Forms Application.  In Asp.net I would create a ListItem and then add it to the listbox

ex.. ListItem li = new ListItem("DisplayValue", "ValueMember);

and then with my list box

lstItems.Add(li);

In windows forms the ListBox.Add() method does not accept a ListItem.

I do not have a DataTable that I can bind to the listbox and use something that looks like this...

lstItems.DataSource = dtItems;
lstItems.DisplayMember = "DisplayColumn";
lstItems.ValueMember = "ValueColumn";

I am using the add method and I'm trying to set the ValueMember with no success...  I will post the code that I am attempting to execute...

private void btnGetProcedures_Click(object sender, System.EventArgs e)
            {
                  lstStoredProcedures.Items.Clear();
                  ListBox.SelectedIndexCollection indexes = lstTables.SelectedIndices;
                  foreach (int index in indexes)
                  {
                        int iTableID = getTableID(lstTables.Items[index].ToString());
                        _intTableID = iTableID;
                        TableStoredProcedures tspTableProcedures = new TableStoredProcedures(_intTableID);
                        _arStoredProcedures = GetStoredProcedures();
                        tspTableProcedures.addStoredProcedures(_arStoredProcedures);
                        _arTableStoredProcedures.Add(tspTableProcedures);
                  
                        foreach(StoredProcedure spProcedure in _arStoredProcedures)
                        {      
                              lstStoredProcedures.Items.Add(spProcedure.ProcedureName);
                              //This is where i need to set the value member...
                        }
                  }
                  
            }
All i need is to set the ValueMember when setting the DisplayMember...
If anyone can help the question is worth 500pts...
Thanks in advance...
Rick