BrianGEFF719
asked on
Angular Acceleration
A) Prove that when an object starts from rest and rotates about a fixed axis wit a constant angular acceleration, the radial acceleration of a point in the object is directly proportional to its angular displacment.
This is how I did this part:
a_rad = w^2*r, where w = omega.
w^2 = w_0^2 + 2a(theta - theta0)
a_rad = 2ar(theta - theta0)
Where a = alpha, r = radius... This part seems correct
B) Through what angle has the object turned at the instant when the resultant accleration of a point makes an angle of 36.9 degrees with the radial acceleration.
I'm not sure how to do this part...
This is how I did this part:
a_rad = w^2*r, where w = omega.
w^2 = w_0^2 + 2a(theta - theta0)
a_rad = 2ar(theta - theta0)
Where a = alpha, r = radius... This part seems correct
B) Through what angle has the object turned at the instant when the resultant accleration of a point makes an angle of 36.9 degrees with the radial acceleration.
I'm not sure how to do this part...
ASKER
How did you determine that the tangential accleration was the y component and the radial was the x component? I thoguht the same thing arctan(y/x), but I didnt know which was which
Brian
Brian
ASKER CERTIFIED SOLUTION
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ASKER
So:
Theta = 1/(2 * tan(36.9))
is this correct?
Theta = 1/(2 * tan(36.9))
is this correct?
ASKER
or .375 radians?
a_tan = r*a
atan(a_tan/a_rad)=36.9 degrees