a_tan = r*a

atan(a_tan/a_rad)=36.9 degrees

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Posted on 2006-04-16

A) Prove that when an object starts from rest and rotates about a fixed axis wit a constant angular acceleration, the radial acceleration of a point in the object is directly proportional to its angular displacment.

This is how I did this part:

a_rad = w^2*r, where w = omega.

w^2 = w_0^2 + 2a(theta - theta0)

a_rad = 2ar(theta - theta0)

Where a = alpha, r = radius... This part seems correct

B) Through what angle has the object turned at the instant when the resultant accleration of a point makes an angle of 36.9 degrees with the radial acceleration.

I'm not sure how to do this part...

This is how I did this part:

a_rad = w^2*r, where w = omega.

w^2 = w_0^2 + 2a(theta - theta0)

a_rad = 2ar(theta - theta0)

Where a = alpha, r = radius... This part seems correct

B) Through what angle has the object turned at the instant when the resultant accleration of a point makes an angle of 36.9 degrees with the radial acceleration.

I'm not sure how to do this part...

5 Comments

a_tan = r*a

atan(a_tan/a_rad)=36.9 degrees

Brian

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