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Vector Functions

Posted on 2006-04-17
Medium Priority
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Im am trying to write a program that will take a vector input and due certain things with the vector such as alternating sums where the first number in the vector is subtracting from the second number and soo on... not sure how to go about writing this code thanks!

int alternating_sum(vector<int> a)
{

}

void display_vector( string vector_name,  vector<int> a)
{
cout << vector_name << " contains the following data: \n";
for (int i=0; i<a.size(); i++)
cout<< a[i] << "  ";
cout<<"\n\n";
}

int main()
{
vector<int>  a(9);
vector<int>  b(7);

a[0] = 1;
a[1] = 4;
a[2] = 9;
a[3] = 16;
a[4] = 9;
a[5] = 7;
a[6] = 4;
a[7] = 9;
a[8] = 11;

b[0] = 11;
b[1] = 11;
b[2] = 7;
b[3] = 9;
b[4] = 16;
b[5] = 4;
b[6] = 1;

// test "alternating_sum" function:

cout << "The alternating sum of vector a is: ";

cout << alternating_sum (a)  << "\n\n";

//test "same_set" function

cout << "The elements of the vectors a and b form ";

if (!same_set(a, b)) cout << "not ";

cout << "the same set.\n\n";

//test "append" function:

display_vector ("Appending a after b generates a new vector that", append(b, a) );

//test "remove duplicates" function:

remove_duplicates(a);
display_vector ("The vector a without duplicates", a );

return 0;
}

0
Question by:Geezy1984
1 Comment

LVL 11

Accepted Solution

WelkinMaze earned 200 total points
ID: 16475520
Hi,

Here are some hints.

Just iterate the vector
for (int i=0; i<a.size(); i++)

and use the remainder of integer division of the index (i) by 2. When the remainder is 0 do addition of a[i] to the sum, if the remainder is 1 do subtraction. Or vice versa.
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