I'm getting a result with a sum of a database column of 21.8

What I then want to be able to do is once I've written the value to a variable is to:

21 (number before the bullet point) x 6 = 126
126 + 8 (number after the bullet point) = 134.... write 134 to another variable
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Suppose $x == "21.8" (the string).

$a=explode('.', $x);
echo $a[0]*6+$a[1];

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Ivo StoykovCommented:
Hello PeterErhard,

$db_var = (int)21.8 * 6;
$another_var = (int)21.8 * 6 + 8;


Ivo StoykovCommented:
Hi PeterErhard,

sorry misunderstood the question

$a = (int)21.8 * 6 + 21.8 % (int)21.8;


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Just to make the situation clearer...

What will you expect to output when the number is, e.g., 12.345 ?
yes you did ivostoykov! since you've just done  
$a = 21 * 6 + 0.8;   // using 0.8 not 8

I suspect KennyTM was right first time.

What happens with trailing 0's, the answer for 1.2 would differ to 1.20

PeterErhardAuthor Commented:
Thanks guys, and yes Kenny was correct the first time. The way the data is being returned and read makes it impossible for there to be two decimal places but thanks for the consideration Waygood, appreciate it :)
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