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\INT sin^4 2x . dx

Posted on 2006-04-20
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How would I integrate sin to the power of 4 ?

I can integrate sin², so I figured I could rewrite it as:

  \INT (sin² 2x)² . dx

But now what?

I'm not looking for someone to solve this for me (although I do already have the correct answer with me), just to point me in the right direction..

Can anyone rewrite that in a form which would perhaps make it obvious of what I should do?

Surely there's no need to use the identity:

   \INT u(dv/dx) . dx = uv - \INT v(du/dx) . dx

for this?


Thanks
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Question by:InteractiveMind
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KennyTM earned 500 total points
ID: 16497490
Hi.

You can use the identity

2 sin² t = 1 - cos 2t
and
2 cos² t = 1 + cos 2t

Hope these help.
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by:InteractiveMind
ID: 16497751
Oh yer, nice one. :)

Thanks.
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