Work with freelancers specializing in everything from database administration to programming, who have proven themselves as experts in their field. Hire the best, collaborate easily, pay securely, and get projects done right.

Solved

Posted on 2006-04-20

How would I integrate sin to the power of 4 ?

I can integrate sin², so I figured I could rewrite it as:

\INT (sin² 2x)² . dx

But now what?

I'm not looking for someone to solve this for me (although I do already have the correct answer with me), just to point me in the right direction..

Can anyone rewrite that in a form which would perhaps make it obvious of what I should do?

Surely there's no need to use the identity:

\INT u(dv/dx) . dx = uv - \INT v(du/dx) . dx

for this?

Thanks

I can integrate sin², so I figured I could rewrite it as:

\INT (sin² 2x)² . dx

But now what?

I'm not looking for someone to solve this for me (although I do already have the correct answer with me), just to point me in the right direction..

Can anyone rewrite that in a form which would perhaps make it obvious of what I should do?

Surely there's no need to use the identity:

\INT u(dv/dx) . dx = uv - \INT v(du/dx) . dx

for this?

Thanks

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Course of the Month16 days, 4 hours left to enroll

Join the community of 500,000 technology professionals and ask your questions.