the combined ages of reena and seens are 44 years and reena is twice as old as seena was when reena was half as old as seena will be when seena is 3 times as old as reena was when reena was 3 times as old as seena.how old r they?
27.5 + 16.5 = 44
reena was 3 times as old as seena when reena was 16.5 and seena was 5.5
3 time as old as that is 49.5
half as old as that is 24.75
seena was 13.75 when reena was 24.75
27.5 = 2*13.75
First rearrange the question a bit and insert some variables (chosen to avoid awkward fractions):
1. The combined ages of Reena (call her age 2A) and Seena (call her age B) are 44 years (2A + B).
2. Reena (2A) is twice as old as:
3. Seena was (A) when Reena was (9C) half as old as:
4. Seena will be (18C) when Seena is (18C) three times as old as:
5. Reena was (6C) when Reena was (6C) three times as old as Seena (2C).
6. How old is Reena (now 2A)?
Ignore the variables and the text is exactly the same as the original question!
At each point of comparison, the difference in their ages (D) is the same, so:
D = 6C - 2C (line 5); D = 9C - A (line 3); and D = 2A - B (line 1)
So 4C = 9C - A, so 2A = 10C
Also 4C = 2A - B, so 4C = 10C - B, so B = 6C
So 2A/B = 10C/6C = 5/3
But 2A+B = 44
So 2A = 27.5
So Reena is 27 years 6 months.
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rena was 3 times as old as seena when reena was 16.5 and seena was 5.5