the age old problem

the combined ages of reena and seens are 44 years and reena is twice as old as seena was when reena was half as old as seena will be when seena is 3 times as old as reena was when reena was 3 times as old as seena.how old r they?
shilpi84Asked:
Who is Participating?

[Product update] Infrastructure Analysis Tool is now available with Business Accounts.Learn More

x
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

ozoCommented:
27.5 and 16.5
rena was 3 times as old as seena when reena was 16.5 and seena was 5.5
shilpi84Author Commented:
how do we figure this out?
ozoCommented:
27.5 + 16.5 = 44
reena was 3 times as old as seena when reena was 16.5 and seena was 5.5
3 time as old as that is 49.5
half as old as that is 24.75
seena was 13.75 when reena was 24.75
27.5 = 2*13.75
sunnycoderCommented:
Answers given by ozo are correct and here is a simple way to reach it:

Start from end of question
>when reena was 3 times as old as seena
Let age of reena be r and age of seena be s ... Then

               R             S
------------------------------------------------
              3s             s   >>when reena was 3 times as old as seena
         
                              9s  >>when seena is 3 times as old as reena
=>
              11s           9s  >>note that difference R-S is constant 2s, so at this point Reena is 11s yrs old

             9/2s                >>when reena was half as old as seena
=>
             9/2s          9/2s - 2s >> constact difference

             9s-4s                  >> reena is twice as old as seena was
=>
              5s             3s

 the combined ages of reena and seens are 44 years
=> 5s + 3s = 44
=> 8s = 44
=> s = 5.5

Hence their ages are
Reena 5 * 5.5 = 27.5
Seens 3 * 5.5 = 16.5

Cheers!
sunnycoder

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
Harisha M GEngineerCommented:
From the page http://72.14.203.104/search?q=cache:d3pyauuW1wEJ:www.puzzlesolver.com/board/viewtopic.php

First rearrange the question a bit and insert some variables (chosen to avoid awkward fractions):

1. The combined ages of Reena (call her age 2A) and Seena (call her age B) are 44 years (2A + B).
2. Reena (2A) is twice as old as:
3. Seena was (A) when Reena was (9C) half as old as:
4. Seena will be (18C) when Seena is (18C) three times as old as:
5. Reena was (6C) when Reena was (6C) three times as old as Seena (2C).
6. How old is Reena (now 2A)?
Ignore the variables and the text is exactly the same as the original question!

At each point of comparison, the difference in their ages (D) is the same, so:

D = 6C - 2C (line 5); D = 9C - A (line 3); and D = 2A - B (line 1)
So 4C = 9C - A, so 2A = 10C
Also 4C = 2A - B, so 4C = 10C - B, so B = 6C
So 2A/B = 10C/6C = 5/3
But 2A+B = 44
So 2A = 27.5
So Reena is 27 years 6 months.
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
Puzzles / Riddles

From novice to tech pro — start learning today.